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galben [10]
2 years ago
13

The statement, "In a chemical reaction, matter is neither created nor destroyed" is called a the Law of Multiple Proportions. b

Dalton's Atomic Theory. c the Law of Definite Proportions. d the Law of Conservation of Mass. e the Scientific Method.
Chemistry
1 answer:
Anettt [7]2 years ago
8 0

Answer:

D

Explanation:

The statement in the question above gives the statement of the law of conservation of matter. The law of conservation of matter states that matter can neither be created nor destroyed but can be converted from one form to another.

This particular law is talking about the indestructible nature of matter. Whatever form of matter we have presently was as a result of the fact that it was converted to from one initial form. It is this fundamental law that guides the operation of a wide number of scientific operations. Things like reaction between substances to form entirely or partially new substances are guided by these fundamental laws of nature

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An iron atom has a mass of ×9.2710−23g and a cooking pot has a mass of 0.500kg
morpeh [17]

The number of iron atoms in a cooking pot that has a mass of 0.500 kg can be solve by dividing it by the mass of the iron atom.

Number of iron atoms = ( 0.5 kg) (1000g / 1kg) ( 1 iron atom / 9.27 x 10^-23 g)

<span>Number of iron atoms = 5.39 x 10 ^24 iron atoms</span>

6 0
2 years ago
Read 2 more answers
Ammonia gas is compressed from 21°C and 200 kPa to 1000 kPa in an adiabatic compressor with an efficiency of 0.82. Estimate the
Evgen [1.6K]

Explanation:

It is known that efficiency is denoted by \eta.

The given data is as follows.

     \eta = 0.82,       T_{1} = (21 + 273) K = 294 K

     P_{1} = 200 kPa,     P_{2} = 1000 kPa

Therefore, calculate the final temperature as follows.

         \eta = \frac{T_{2} - T_{1}}{T_{2}}    

         0.82 = \frac{T_{2} - 294 K}{T_{2}}    

          T_{2} = 1633 K

Final temperature in degree celsius = (1633 - 273)^{o}C

                                                            = 1360^{o}C

Now, we will calculate the entropy as follows.

       \Delta S = nC_{v} ln \frac{T_{2}}{T_{1}} + nR ln \frac{P_{1}}{P_{2}}

For 1 mole,  \Delta S = C_{v} ln \frac{T_{2}}{T_{1}} + R ln \frac{P_{1}}{P_{2}}

It is known that for NH_{3} the value of C_{v} = 0.028 kJ/mol.

Therefore, putting the given values into the above formula as follows.

     \Delta S = C_{v} ln \frac{T_{2}}{T_{1}} + R ln \frac{P_{1}}{P_{2}}

                = 0.028 kJ/mol \times ln \frac{1633}{294} + 8.314 \times 10^{-3} kJ \times ln \frac{200}{1000}

                = 0.0346 kJ/mol

or,             = 34.6 J/mol             (as 1 kJ = 1000 J)

Therefore, entropy change of ammonia is 34.6 J/mol.

3 0
2 years ago
It takes 839./kJmol to break a carbon-carbon triple bond. Calculate the maximum wavelength of light for which a carbon-carbon tr
tresset_1 [31]

Answer:

The maximum wavelength of light for which a carbon-carbon triple bond could be broken by absorbing a single photon is 143 nm.

Explanation:

It takes 839 kJ/mol to break a carbon-carbon triple bond.

Energy required to break 1 mole of carbon-carbon triple bond = E = 839 kJ

E = 839 kJ/mol = 839,000 J/mol

Energy required to break 1 carbon-carbon triple bond = E'

E'=\frac{ 839,000 J/mol}{N_A}=\frac{839,000 J}{6.022\times 10^{23} mol^{-1}}=1.393\times 10^{-18} J

The energy require to single carbon-carbon triple bond will corresponds to wavelength which is required to break the bond.

E'=\frac{hc}{\lambda } (Using planks equation)

\lambda =\frac{6.626\times 10^{-34} Js\times 3\times 10^8 m/s}{1.393\times 10^{-18} J}

\lambda =1.427\times 10^{-7} m =142.7 nm = 143 nm

(1 m = 10^9 nm)

The maximum wavelength of light for which a carbon-carbon triple bond could be broken by absorbing a single photon is 143 nm.

6 0
2 years ago
The number of p atoms in 1.0 g of ba3(po4)2 is:
marta [7]
First, we determine the number of moles of barium phosphate. This is done using:

Moles = mass / Mr
Moles = 1 / 602
Moles = 0.002

Now, we see from the formula of the compound that each mole of barium phosphate has 2 moles of phosphorus (P). Therefore, the moles of phosphorus are:
0.002 * 2 = 0.004

The number of particles in one mole of substance is 6.02 x 10²³. The number of phosphorus atoms will be:
0.004 * 6.02 x 10²³

2.41 x 10²¹ atoms of phosphorus are present
3 0
2 years ago
An unknown compound melting at 131 - 133 C. It is thought to be one of the following compounds: trans-cinnamic acid (133-134); b
Vesnalui [34]

Answer:

benzamide

Explanation:

Compound            melting Point ,ºC          Melting Pont Mixture, ºC

       X                          131 - 133

trans-cinnamic            133 - 134                      110 - 120

acid

benzamide                 128 - 130                       130-132

malic acid                   131   -133                        114 -124

Benzoin                      135 - 137                        108 - 116

The compound X is benzamide since the melting point range is the one closest to this compound (  130-132 ºC)

The reason there is not an exact match is not due due to the presence of impurities. The presence of impurities always lower the melting point ( it is a coligative property such as the melting point depresion of salt and water )

The reason for the deviation must be  be some other factors such as preparation of the sample in the capillary, errors in reading the thermometer, rate of heating, etc.

5 0
2 years ago
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