A circular pond with a radius of 1.5 metres has a 20-inch border around it.
1 answer:
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Answer:
a) quotient = 2, remainder = 5
b) quotient = -10, remainder = -1
c) quotient = 34, remainder = 7
d) quotient = 77, remainder = 0
e) quotient = 0, remainder = 0
f) quotient = 0, remainder = 3
g) quotient = 0, remainder = -1
h) quotient = 4, remainder = 0
Step-by-step explanation:
The relationship between the quotient, remainder and divisor is that the product of the quotient and divisor added to the reminder gives the dividend.
Based on this, when
a)19 is divided by 7 = 19/7
= 2
Hence the quotient is 2, the remainder is 5
Applying the same principle, when
b) −111 is divided by 11
= -10
Hence the quotient is -10, the remainder is -1
c) 789 is divided by 23
=34
Hence the quotient is 34, the remainder is 7
d) 1001 is divided by 13
= 77
Hence the quotient = 77, the remainder is 0
e) 0/19 = 0
Hence the quotient is 0, the remainder is 0
f) 3/5
Hence the quotient is 0, the remainder is 3
g) -1/3
Hence the quotient is 0, the remainder is -1
h) 4/1
Hence the quotient is 4, the remainder is 0
If <span>r^2=x^2+y^2 then
</span>y^2=r^2-x^2
y=
</span>y^2=r^2-x^2
y=