First subtract 1.75n-2n-1.25n then you subtract 75 80 and 90 then you divide by n
(a) The probability that there is no open route from A to B is (0.2)^3 = 0.008.
Therefore the probability that at least one route is open from A to B is given by: 1 - 0.008 = 0.992.
The probability that there is no open route from B to C is (0.2)^2 = 0.04.
Therefore the probability that at least one route is open from B to C is given by:
1 - 0.04 = 0.96.
The probability that at least one route is open from A to C is:

(b)
α The probability that at least one route is open from A to B would become 0.9984. The probability in (a) will become:

β The probability that at least one route is open from B to C would become 0.992. The probability in (a) will become:

Gamma: The probability that a highway between A and C will not be blocked in rush hour is 0.8. We need to find the probability that there is at least one route open from A to C using either a route A to B to C, or the route A to C direct. This is found by using the formula:


Therefore building a highway direct from A to C gives the highest probability that there is at least one route open from A to C.
Answer:
its 8 2/3
Step-by-step explanation: I got it right on edg
Answer:1/12 left
Step-by-step explanation: you should switch both into the same denominator for the fractions so that would turn into 3/12 and 8/12 then add them up to get 11/12 so he has 1/12 left
I think it’s 5.25 cm but you might want to double check.