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wlad13 [49]
2 years ago
13

Write a hypothesis about the use of an object’s physical characteristics to determine its density. Use the format "if . . . then

. . . because . . .” and be sure to answer the lesson question "How can the density of an object be determined?”
Physics
2 answers:
kari74 [83]2 years ago
4 0

The density of an object is the mass of the object divided by its volume.

Remember that mass of an object is the amount of matter that the object contains. The unit for mas in the standard international unit system is the kilogram (kg), which is 1000 grams; the unit of mass in the US is the pound (lb), which is 453.592 grams.

The volume of an object is the amount of space that the object occupies. The unit for volume in the standard international unit system are the cubic meter (m^3) and the liter (L); 1 cubic meter equals 1000 liters.

The density of an object is the quantity of mass of the object per unit of its volume. The unit for mas in the standard international unit system is the kilogram per cubic meter (\frac{kg}{m^3}).

Now, lets create our hypothesis:

If the mass and the volume of and object are known, then its density can be calculated dividing the object's mass by its volume.

We can conclude that the density of an object can be obtained by dividing its mass by its volume.

Neporo4naja [7]2 years ago
4 0

Explanation :

Density is defined as mass per unit volume.

i.e. \rho=\dfrac{mass}{volume}

Mass of an object is the amount of matter contained in the body. The mass of the body remains the same. It is a scalar quantity.

Volume of an object is the space occupied by it.

So, the density of an object depends on its mass and its volume.

<em>If the mass of an object increases then its density increases because density is directly proportional to mass.</em>

<em>Similarly, If the volume of an object increases then its density decreases because density is inversely proportional to volume.</em>

The density of an object is determined by knowing its mass and ts volume. The mass should be in grams and volume is in mL or cm^3.

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A satellite that orbits Earth with a speed of v0 must be in an orbit of radius 8RE to maintain a circular orbit, where RE is the
NISA [10]

Answer:

1.024 × 10⁸ m

Explanation:

The velocity v₀ of the orbit 8RE is v₀ = 8REω where ω = angular speed.

So, ω =  v₀/8RE

For the orbit with radius R for it to maintain a circular orbit and velocity 2v₀, we have

2v₀ = Rω

substituting ω =  v₀/8RE into the equation, we have

2v₀ = v₀R/8RE

dividing both sides by v₀, we have

2v₀/v₀ = R/8RE

2 = R/8RE

So, R = 2 × 8RE

R = 16RE

substituting RE = 6.4 × 10⁶ m

R = 16RE

= 16 × 6.4 × 10⁶ m

= 102.4 × 10⁶ m

= 1.024 × 10⁸ m

8 0
2 years ago
if forces acting on an object are unbalanced, which factors may result from an unbalanced force? Check all that apply. The net f
Alchen [17]
The net force is negative, and there is a change in motion.
8 0
2 years ago
Read 2 more answers
A box rests on the (horizontal) back of a truck. The coefficient of static friction between the box and the surface on which it
vredina [299]

Answer:

The distance is 11 m.

Explanation:

Given that,

Friction coefficient = 0.24

Time = 3.0 s

Initial velocity = 0

We need to calculate the acceleration

Using newton's second law

F = ma...(I)

Using formula of friction force

F= \mu m g....(II)

Put the value of F in the equation (II) from equation (I)

ma=\mu mg....(III)

a = \mu g

Put the value in the equation (III)

a=0.24\times9.8

a=2.352\ m/s^2

We need to calculate the distance,

Using equation of motion

s = ut+\dfrac{1}{2}at^2

s=0+\dfrac{1}{2}2.352\times(3.0)^2

s=10.584\ m\ approx\ 11\ m

Hence, The distance is 11 m.

3 0
2 years ago
Kara Less was applying her makeup when she drove into South's busy parking lot last Friday morning. Unaware that Lisa Ford was s
exis [7]

Answer

given,

Mass of Kara's car = 1300 Kg

moving with speed = 11 m/s

time taken to stop = 0.14 s

final velocity = 0 m/s

distance between Lisa ford and Kara's car = 30 m

a) change in momentum of Kara's car

  Δ P = m Δ v                  

  \Delta P = m (v_f-v_i)

  \Delta P = 1300 (0 - 11)

  Δ P = - 1.43 x 10⁴ kg.m/s

b) impulse is equal to change in momentum of the car

    I = - 1.43 x 10⁴ kg.m/s

c) magnitude of force experienced by Kara

  I = F x t

 I is impulse acting on the car

 t is time

  - 1.43 x 10⁴= F x 0.14

    F = -1.021 x 10⁵ N

negative sign represents the direction of force

8 0
2 years ago
Read 2 more answers
A fireboat is to fight fires at coastal areas by drawing seawater with a density of 1030 kg/m3 through a 10-cm-diameter pipe at
GaryK [48]

Answer:

50.93 m/s

199.5 kW

Explanation:

From the question, the nozzle exit diameter = 5 cm, Radius= diameter/2= 5cm/2= 2.5cm. we can convert it to metre for unit consistency= (2.5×0.01)=

0.025m

We can calculate the The cross sectional area of the nozzle as

A= πr^2

A= π ×0.025^2

= 1.9635 ×10^- ³ m²

From the question, the water is moving through the pipe at a rate of 0.1 m /s , then for the water to move through it at a seconds, it must move at

(0.1 / 1.9635 ×10^- ³ m²)

= 50.93 m/s

During the Operation of the pump, the Dynamic energy of the water= potential energy provided there is no loss during the Operation

mgh = 1/2mv²

We can make "h" subject of the formula, which is the height of required head of water

h = (1/2mv²)/mg

h= v² / 2g

h = 50.93² / (2 ×9.81)

h = 132.21m

From the question;

The total irreversible head loss of the system = 3 m,

the given position of nozzle = 3 m

the total head the pump needed=(The total irreversible head loss of the system + the position of the nozzle + required head of water )

=(3 + 3 + 132.21m)

=138.21m

mass of water pumped in a seconds can be calculated since we know that mass is a product of volume and density

Volume= 0.1m³

Density of sea water=1030 kg/m

(0.1 m^3× 1030)

= 103kg

We can calculate the Potential enegry, which is = mgh

= (103 ×9.81 × 138.21)

= 139651.5 Watts

= 139.65kW

To determine required shaft power input to the pump and the water discharge velocity

Energy= efficiency × power

But we are given efficiency of 70 percent, then

139651.5 Watts = 0.7P

=199502.18 Watts

P=199.5 kW

Therefore, the required shaft power input to the pump and the water discharge velocity is 199.5 kW

5 0
1 year ago
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