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I am Lyosha [343]
2 years ago
5

A tractor tire travels about 471 inches in 1 rotation. What is the approximate diameter of the tire?

Mathematics
1 answer:
BartSMP [9]2 years ago
4 0

Answer:184

Step-by-step explanation:

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MissTica

Answer:

a on edge

Step-by-step explanation:

i took the cumulative exam

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In the diagram, AB and EF are horizontal lines and CB is a vertical line segment. If FB : FC = 4 : 3, what are the coordinates o
sergij07 [2.7K]
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On Sasha's desk there are c green notebooks. The number of red notebooks on her desk is 6 less than number of green notebooks. H
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Sasha's desk has c green notebooks.

The number of red notebooks on her desk is c-6.

Sasha's desk has either green or red notebooks.

The total number of notebooks on Sasha's notebook is c+c-6=2c-6.



7 0
2 years ago
Susan and ronald dugan agreed upon the price of 256,000 for their new home. They plan to make 30 percent down payment and financ
Eduardwww [97]

Answer:

The total amount to be paid for new home is $838,014.72  

Step-by-step explanation:

Given as :

The price of the new house = $256,000

The down payment amount = 30% of house price

So, The down payment price =  30% of $256,000

i.e The down payment price =  \dfrac{30}{100} × 256000

Or, The down payment price = $76,800

Now, rest amount is finance

So, The finance Amount = p = $256000 - $76800 = $179,200

The rate of interest applied = r = 7.5%

The time period of finance = t = 20 years

Let The Amount after 20 years of finance = $A

Let The total amount to be paid for new home = $B

<u>Now, From Compound Interest </u>

Amount = Principal × (1+\dfrac{\textrm rate}{100})^{\textrm time}

Or, A = p × (1+\dfrac{\textrm r}{100})^{\textrm t}

Or, A = $179,200 × (1+\dfrac{\textrm 7.5}{100})^{\textrm 20}

Or, A = $179,200 × (1.075)^{\textrm 20}

Or, A = $179,200 × 4.24785

∴  A = $761,214.72

So,The Amount after 20 years of finance = A = $761,214.72

<u>Now, Again</u>

The total amount to be paid for new home = Down payment amount + The Amount after 20 years of finance

Or, B = $76,800 + A

Or, B = $76,800 + $761,214.72

Or, B = $838,014.72

So, The total amount to be paid for new home = B = $838,014.72

Hence, The total amount to be paid for new home is $838,014.72  Answer

7 0
2 years ago
"Immediately after a ban on using hand-held cell phones while driving was implemented, compliance with the law was measured. A r
sergiy2304 [10]

Answer:

(a) Null Hypothesis, H_0 : p_1-p_2=0  or  p_1= p_2  

    Alternate Hypothesis, H_A : p_1-p_2\neq 0  or  p_1\neq p_2

(b) We conclude that there is a statistical difference in these two proportions measured initially and then one year later.

Step-by-step explanation:

We are given that a random sample of 1,250 drivers found that 98.9% were in compliance. A year after the implementation, compliance was again measured to see if compliance was the same (or not) as previously measured.

A different random sample of 1,100 drivers found 96.9% compliance."

<em />

<em>Let </em>p_1<em> = proportion of drivers that were in compliance initially</em>

p_2<em> = proportion of drivers that were in compliance one year later</em>

(a) <u>Null Hypothesis</u>, H_0 : p_1-p_2=0  or  p_1= p_2      {means that there is not any statistical difference in these two proportions measured initially and then one year later}

<u>Alternate Hypothesis</u>, H_A : p_1-p_2\neq 0  or  p_1\neq p_2     {means that there is a statistical difference in these two proportions measured initially and then one year later}

The test statistics that will be used here is <u>Two-sample z proportion statistics</u>;

                     T.S.  = \frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{ \frac{\hat p_1(1-\hat p_1)}{n_1} + \frac{\hat p_2(1-\hat p_2)}{n_2}} }  ~ N(0,1)

where, \hat p_1 = sample proportion of drivers in compliance initially = 98.9%

\hat p_2 = sample proportion of drivers in compliance one year later = 96.9%

n_1 = sample of drivers initially = 1,250

n_2 = sample of drivers one year later = 1,100

(b) So, <u><em>the test statistics</em></u>  =  \frac{(0.989-0.969)-(0)}{\sqrt{ \frac{0.989(1-0.989)}{1,250} + \frac{0.969(1-0.969)}{1,100}} }  

                                           =  3.33

<u>Now, P-value of the test statistics is given by;</u>

         P-value = P(Z > 3.33) = 1 - P(Z \leq 3.33)

                                            = 1 - 0.99957 = <u>0.00043</u>

Since in the question we are not given with the level of significance so we assume it to be 5%. Now at 5% significance level, the z table gives critical values between -1.96 and 1.96 for two-tailed test.

<em>Since our test statistics does not lies within the range of critical values of z, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which </em><u><em>we reject our null hypothesis.</em></u>

Therefore, we conclude that there is a statistical difference in these two proportions measured initially and then one year later.

7 0
2 years ago
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