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GREYUIT [131]
2 years ago
6

An observer at sea level does not hear an aircraft that is flying at an altitude of 7000 m until it is a distance of 13 km from

the observer. Estimate the Mach number at which the aircraft is flying. In arriving at the answer, assume that the average temperature of the air between sea level and 7000 m is –10°C
Engineering
1 answer:
garik1379 [7]2 years ago
5 0

Answer:

The answer is 2.109

Explanation:

C = \sqrt{kRT} = \sqrt{(1.4) (287) (163)}  = 325.1 m/s\\\\tan \alpha = \frac{7000}{13000} = 0.5385\\\alpha  = 28.3\\\\M = \frac{1}{sen \alpha } = 2.109

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Oliver is designing a new children’s slide to increase the speed at which a child can descend. His first design involved steel b
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Answer:

The correct option is;

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Explanation:

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8 0
2 years ago
If water molecules pass through a membrane with a steady state flux of 220 mole/(m2 day), how long will it take, in hours, for 0
goblinko [34]

Answer:

<em>0.0386 hr</em>

<em></em>

Explanation:

Area = 565 cm^2 = 0.0565 m^2  (1 cm^2 = 0.0001 m^2)

flux state rate = 220 mole/m^2-day

<em>There are 24 hrs in a day,</em> therefore rate in hrs will be

220/24 = 9.17 mole/m^2-hr

mass of water = 0.4 kg

molar mass of water = (1 x 2) + 16 = 18 kg/mole

therefore,

<em>mole of water = mass of water/molar mass of water</em>

mole of water = 0.4/18 = 0.02 mole

<em>mole flux = mole/area</em> = 0.02/0.0565 = 0.354 mol/m^2

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7 0
2 years ago
During normal operation, an electrical component experiences a constant rate of ohmic dissipation ini g = 0.01 W that causes the
Llana [10]

Answer:

Check the explanation

Explanation:

Kindly check the attached image below for the step by step explanation to your answer.

4 0
2 years ago
A single crystal of a metal that has the FCC crystal structure is oriented such that a tensile stress is applied parallel to the
bagirrra123 [75]

The magnitude of applied stress in the direction of 101 is 12.25 MPA and in the direction of 011, it is not defined.                                          

Explanation:        

Given:

tensile stress is applied parallel to the [100] direction

Shear stress is 0.5 MPA.

To calculate:

The magnitude of applied stress in the direction of [101] and [011].

Formula:

zcr=σ cosФ cosλ

Solution:

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cosλ = (1)(1)+(0)(0)+(0)(1)/√(1)(2)

cos λ = 1/√2

The magnitude of stress in the direction of 101 is 12.25 MPA

In the direction of 011

We have an angle between 100 and 011

cosλ = (1)(0)+(0)(-1)+(0)(1)/√(1)(2)

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Therefore the magnitude of stress to cause a slip in the direction of 011 is not defined.                                                                                                                                      

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2 years ago
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