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DiKsa [7]
2 years ago
3

Use pictures or words to explain how you would use the make a ten strategy to solve 5+7

Mathematics
2 answers:
kiruha [24]2 years ago
6 0
Add zeros to 50 and 70 and add them both
Yuki888 [10]2 years ago
3 0
Just add zeros to the end and it will make the problem 50+70=120, then take the zeros away and it's 5+7=12
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Complete the statements about the key features of the graph of f(x) = x5 – 9x3. As x goes to negative infinity, f(x) goes to neg
Mars2501 [29]
The function is f(x)= x^{5} -9x ^{3}

1. let's factorize the expression x^{5} -9x ^{3}:

f(x)= x^{5} -9x ^{3}= x^{3} ( x^{2} -9)=x^{3}(x-3)(x+3)

the zeros of f(x) are the values of x which make f(x) = 0.

from the factorized form of the function, we see that the roots are:

-3, multiplicity 1
3, multiplicity 1
0, multiplicity 3

(the multiplicity of the roots is the power of each factor of f(x) )


2.  
The end behavior of f(x), whose term of largest degree is x^{5}, is the same as the end behavior of  x^{3}, which has a well known graph. Check the picture attached. 

(similarly the end behavior of an even degree polynomial, could be compared to the end behavior of x^{2})

so, like the graph of x^{3}, the graph of f(x)= x^{5} -9x ^{3} :

"As x goes to negative infinity, f(x) goes to negative infinity, and as x goes to positive infinity, f(x) goes to positive infinity. "

7 0
2 years ago
Read 2 more answers
Frogs a b c d had a jumping relay race how many centimeters did they jump altogether ? 27 centimeters 34, 25, 28?
inysia [295]
114.
Just add all of them and that's it :)
6 0
2 years ago
r Flag For Review A certain city with a population of 132,000 is to be divided into 11 voting districts, and no district is to h
Alex787 [66]

Answer:

P = \frac{132000}{12}=11000

So then P =11000 is the minimum that the least populated district could have.

Step-by-step explanation:

We have a big total of N = 132000 for the population.

And we know that we divide this population into 11 districts

And we have this info given "no district is to have a population that is more than 10 percent greater than the population of any other district"

Let's assume that P represent our minimum value for a district in the population. The range of possible values for the population of each district would be between P and 1.1 P

The interest on this case is find the minimum value for P and in order to do this we can assume that 1 district present the minimum and the other 10 the maximum value 1.1P in order to find which value of P satisfy this condition, and we have this:

P + 10 (1.1P) = 12 P= 132000

P = \frac{132000}{12}=11000

So then P =11000 is the minimum that the least populated district could have.  

3 0
2 years ago
A rectangle has height and width changing in such a way that the area remains constant 2 square feet. At the instant the height
hichkok12 [17]

Answer:

\frac{1}{3} ft/min is the rate of changing of width

Step-by-step explanation:

Given -

The area always remain constant i.2 2 square feet.

Height of the rectangle = 2 feet

Rate of changing of height = 6 feet per minute

Since area is constant

2 sq ft = (2 * 6) ft/min * 1 * x ft/min

x = \frac{1}{3} ft/min

4 0
2 years ago
Alexis wanted to understand whether grade level had any relationship to their opinion on extending the school day. She surveyed
MakcuM [25]

Actually there is enough information to solve this problem. First, let us find the total per row and per column.


 (see attached pic)


P(Grade 10 | opposed) with P(opposed | Grade 10)

P(Grade 10 | opposed) = Number in Grade 10 who are opposed / Total number of Opposed (column)

P(Grade 10 | opposed) = 13 / 41 = 0.3171

 

P(opposed | Grade 10) = Number in Grade 10 who are opposed / Total number in Grade 10 (row)

P(opposed | Grade 10) = 13 / 32 = 0.4063

 

Therefore:

P(Grade 10 | opposed) IS NOT EQUAL P(opposed | Grade 10), hence they are dependent events.

 

Answer:

P(Grade 10 | opposed) < P(opposed | Grade 10)

6 0
2 years ago
Read 2 more answers
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