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DedPeter [7]
2 years ago
11

Which question is best answered by an experiment?a. Does a flipped-classroom format increase student success rates in English? b

. Is successful completion of a college-level English class within two years of enrolling in college linked with earning a degree or certificate? c. Is entering the remedial English sequence at three levels below transfer associated with lower success rates in subsequent general education classes? d. Are students who participate in an accelerated pathway through college-level English more likely to pass a college-level English class?
Mathematics
1 answer:
mario62 [17]2 years ago
3 0

Answer:

The correct option is d.

Step-by-step explanation:

For a question to be answered by an experiment, some conditions need to be satisfied.

An experiment must follow qualitative analysis. In a sense, an experiment must be able to be quantified. Let's take an example:

Suppose a school wants to screen candidates for an entrance level. The candidates must be of a specified number. The exam is taken. The exam scores are tabulated and distributed according to the statistical distribution. In this way, the quantitative distribution in the candidates pass mark cab be quantified.

In the question, the correct option will be d. The program can be tested quantitatively (and generating data).

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Aisha helps out at a petting zoo over the summer. She makes some changes where the animals are kept.
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I believe the awnser is A
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All students are classified as either full-time or part-time. Kenneth conducted a survey in which he collected data on the perce
Crank

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A

Step-by-step explanation:

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Car a leaves the grand canyon at noon. it travels at 60 mph, but stops at 3 pm for an hour. car b leaves the grand canyon at 2 p
kupik [55]
3:30pm .................
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4. Suppose that Peculiar Purples and Outrageous Oranges are two different and unusual types of bacteria. Both types multiply thr
Viktor [21]

Answer:

Peculiar purples would be more abundant

Step-by-step explanation:

Given that eculiar Purples and Outrageous Oranges are two different and unusual types of bacteria. Both types multiply through a mechanism in which each single  bacterial cell splits into four. Time taken for one split is 12 m for I one and 10 minutes for 2nd

The function representing would be

i) P=P_0 (4)^{t/12} for I bacteria where t is no of minutes from start.

ii) P=P_0 (4)^{t/10} for II bacteria where t is no of minutes from start. P0 is the initial count of bacteria.

a) Here P0 =3, time t = 60 minutes.

i) I bacteria P = 3(4)^{5} =3072

ii) II bacteria P = 3(4)^{4} =768

b) Since II is multiplying more we find that I type will be more abundant.

The difference in two hours would be

3(4)^{10}- 3(4)^{8} =2949120

c) i) P=P_0 (4)^{t/12} for I bacteria where t is no of minutes from start.

ii) P=P_0 (4)^{t/10} for II bacteria where t is no of minutes from start. P0 is the initial count of bacteria.

d) At time 36 minutes we have t = 36

Peculiar purples would be

i) P=3 (4)^{36/12}=192

The rate may not be constant for a longer time.  Hence this may not be accurate.

e) when splits into 2, we get

P=P_o (2^t) where P0 is initial and t = interval of time

7 0
2 years ago
A study is being conducted in which the health of two independent groups of ten policyholders is being monitored over a one-year
uysha [10]

Answer:

46.91% probability that at least nine participants complete the study in one of the two groups, but not in both groups

Step-by-step explanation:

We use two binomial trials to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Probability of at least nine participants finishing the study in a group.

0.2 probability of a students dropping out. So 1 - 0.2 = 0.8 probability of a student finishing the study. This means that p = 0.8.

10 students, so n = 10

We have to find:

P(X \geq 9) = P(X = 9) + P(X = 10)

Then

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 9) = C_{10,9}.(0.8)^{9}.(0.2)^{1} = 0.2684

P(X = 10) = C_{10,10}.(0.8)^{10}.(0.2)^{0} = 0.1074

P(X \geq 9) = P(X = 9) + P(X = 10) = 0.2684 + 0.1074 = 0.3758

0.3758 probability that at least nine participants complete the study in a group.

Calculate the probability that at least nine participants complete the study in one of the two groups, but not in both groups?

0.3758 probability that at least nine participants complete the study in a group. This means that p = 0.3758

Two groups, so n = 2

We have to find P(X = 1).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{2,1}.(0.3758)^{1}.(0.6242)^{1} = 0.4691

46.91% probability that at least nine participants complete the study in one of the two groups, but not in both groups

5 0
2 years ago
Read 2 more answers
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