If the object distance in the following picture were 8.0 m and the image distance were 2.0 m, and the object is 0.50 m tall, how
1 answer:
Height of the image: -0.125 m, inverted
Explanation:
We can solve this problem by using the magnification equation for mirrors/lenses:
where
q is the distance of the image from the mirror
p is the distance of the object from the mirror
y' is the height of the image
y is the height of the object
For the object in this problem, we have:
p = 8.0 m
q = 2.0 m
y = 0.50 m
Therefore, we can solve for y', the height of the image:
And the negative sign means the image is inverted.
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Answer:
Explanation:
Suppose the distance between the two cities is D and the velocity in calm weather is V . The total time taken in two way travel is given by
Total distance / velocity
= 2 D / V
Suppose velocity of wind is v . Then in one way the velocity of airplane will become V + v and in the return trip its velocity will be V - v
Total time taken
=
=
=
=
= The denominator contains a factor
which is less than one so time calculated will be more than
2D / V
Hence in the second case time taken will be more .
After 6 seconds, the car will surpass the cyclist.
<h3><u>Explanation:</u></h3>The speed of the cyclist = 6 m/s.
Let after time t sec, the car will overtake the cyclist.
So, distance covered by the cyclist in t sec = 6t m
Initial velocity of the car is 0 m/s, because the car is just starting.
Acceleration of the car =.
Final velocity of the car =6 m/s.
So to cover the distance 6t, the time required by the car =
t =6 sec
So, after 6 seconds, the car will surpass the cycle.
Answer:
Explanation:
The electric field produced by a single point charge is given by:
where
k is the Coulomb's constant
q is the charge
r is the distance from the charge
In this problem, we have
E = 1.0 N/C (magnitude of the electric field)
r = 1.0 m (distance from the charge)
Solving the equation for q, we find the charge: