Answer:
C-chart is the best suited for this since it is widely used to determine if the defects or returns are within the control limits or not.
Mean = average = 8 per day
Z=3
UcL = mean + 3[square root of mean]= 8+ 3 (Sq root of 8) = 16.48
LcL= mean - 3[ square foot of mean] = - 0.485
So the returns are within the control limits.
Answer:
depreciation expense = $25800 debit
accumulated depreciation = $25800 credit
Explanation:
given data
beginning of the year cost = $135,000
useful life = 5 years
product = 300,000 units
salvage value = $15,000
1st year machine produce = 64,500 units
to find out
machines first year depreciation
solution
we get here machines first year depreciation that is express as
machines depreciation = ( depreciation base ÷ estimate unit produce ) × no of unit produce in 1st year ...................1
put here value we get
machines depreciation =
× 64500
machines depreciation = $25800
so here
depreciation expense = $25800 debit
accumulated depreciation = $25800 credit
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Answer:
Ke = D1/Po(1-F) + g
Ke = $0.65/17(1-0.1) + 0.06
Ke = 0.0425 + 0.06
ke = 0.1025 = 10.25%
WACC = Ke(E/V) + Kd(D/V)(1-T)
WACC = 10.25(55/100) + 7.75(45/100)(1-0.4)
WACC = 5.6375 + 2.0925
WACC = 7.73%
Explanation:
In this case, there is need to calculate cost of equity in the light of floatation cost using the above formula. Thus, we will now calculate WACC by considering cost of equity and the proportion of equity in the capital structure plus after-tax cost of debt and the proportion of debt in the capital structure.
Answer:
Correct option is B.
<u>Asset A</u>
Explanation:
Reward to variability ratio = return/σ
Asset A,σ = 15/0.4 = 37.5
Asset B,σ = 20/0.3 = 66.67
Since deviation(volatility) is lesser for asset A,a risk investor would prefer asset A.