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vredina [299]
2 years ago
12

Fire load (MJ/m2) is the heat energy that could be released per square meter of floor area by combustion of contents and the str

ucture itself. The following cumulative percentages are for fire loads in a sample of 388 rooms:
Fire load (MJ/m2) is the heat energy that could be
Value 0 150 300 450 600 750 900
Cumulative % 0 19.0 37.0 61.9 76.5 86.3 93.0
Value 1050 1200 1350 1500 1650 1800 1950
Cumulative % 95.0 97.8 98.1 99.5 99.6 99.8 100.0
(a) What proportion of fire loads are less than 600? At least 1200? (Round your answers to three decimal places.)
(b) What proportion of the loads are between 600 and 1200? (Round your answer to three decimal places.)
Mathematics
1 answer:
mestny [16]2 years ago
8 0

Answer:

a)

The proportion of fire loads are less than 600 is 0.765

The proportion of fire loads at least 1200 is 0.022

b)

The proportion of the loads between 600 and 1200 is 0.213

Step-by-step explanation:

The cumulative percent is given for various values of x.

Value (x)      Cumulative percent

0                   0

150              0.19

300             0.37

450             0.619

600             0.765

750             0.863

900             0.93

1050            0.95

1200            0.978

1350            0.981

1500            0.995

1650           0.996

1800          0.998

1950           1

a)

The proportion of fire loads are less than 600

P(x<600)=F(600)=0.765

Because we are given the cumulative percentages and the cumulative percentage for 450 will represent the proportion of fire loads that are less than 600.

The proportion of fire loads at least 1200

P(X≥1200)=1-F(1200)=1-0.978=0.022

b)

The proportion of the loads between 600 and 1200

P(600≤X≤1200)=?

P(a≤X≤b)=F(b)-F(a)

P(600≤X≤1200)=F(1200)-F(600)=0.978-0.765=0.213

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sattari [20]

Answer:

279 silvery minnow

Step-by-step explanation:

Number of Silvery Minnows initially tagged = 54

Number of minnows captured = 62

Number of tagged minnows in captured ones = 12

Remember that in the very beginning there were no tagged minnows. 54 minnows were captured, tagged and released. This means, there are total 54 tagged minnows in the entire population. Lets say there are x number of minnows in total.

So, in x minnows, 54 are tagged ones.

When 62 minnows are captured, only 12 are tagged ones and remaining are un-tagged. Since, the minnows were randomly captured, we can develop a proportion from this case to estimate the total population of minnows in the Rio Grande River.

Ratio of tagged minnows to total population must be equal to the ratio of captured tagged minnows in total captured minnows.

i.e.

54 : x = 12 : 62\\\\ \frac{54}{x} = \frac{12}{62}\\\\ 62(54)=12x\\ \\ x = 279

This means, there were 279 silvery minnows in the Rio Grande River.

3 0
2 years ago
Here is the histogram of a data distribution. All class widths are 1. What is the median of this distribution?
Bingel [31]

Answer:

The median is 4.

Step-by-step explanation

if you layout all the number, you get

1,2,2,3,3,3,4,5,5,5,6,6,7

So, to find the median you find the number(s) right in the middle.

(Ex. 3,4,5; 4 is the median)

(Ex. 3,4,5,7; 4.5 is the answer)

The middle number of

1,2,2,3,3,3,4,5,5,5,6,6,7

is 4, so 4 is the median.

hope this helps. :)

6 0
2 years ago
Hailey paid \$13$13dollar sign, 13 for 1\dfrac3{7} \text{ kg}1 7 3 ​ kg1, start fraction, 3, divided by, 7, end fraction, start
hichkok12 [17]

Answer:

1kg of salami cost $9.1

Step-by-step explanation:

Hailey paid $13 for 1 3/7 kg of sliced salami.

What was the cost per kilogram of salami?

Cost of 1 3/7 kg of sliced salami=$13

1 3/7 kg=10/7kg

Let x=1 kg of sliced salami

10/7 kg of x=$13

$13=10/7x

13=10/7*x

x=13 ÷ 10/7

=13×7/10

=91/10

=9.1

x=$9.1

Therefore, 1kg of salami cost $9.1

8 0
2 years ago
Below is the number of pages in each of the six books that Pedro read this summer. \begin{aligned} &amp;584, 201, 255, \\ &amp;4
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Answer:

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Know that the probability frequency is:

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What is the median of the following 7 scores?
dybincka [34]
First, you want to put all the numbers in order from least to greatest.

21, 33, 33, 42, 67, 79, 89

Now, you can use this song to help remember how to do these problems.

Cross off the sides till you get to the center. 1 is good, 2 is bad. (If you get two numbers in the middle) add then divide by two.

Cross off 21, then 89, then 33, then 79, then 33, then 67. Now, you're left with 42 in the middle. That is your median. Hope this helps! :)
8 0
2 years ago
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