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attashe74 [19]
2 years ago
7

Find a solution to the initial value problem y′+sin(t)y=g(t), y(0)=3, that is continuous on the interval [0,2π] where g(t)={sin(

t)−sin(t)if 0≤t≤π,if π
Mathematics
1 answer:
denpristay [2]2 years ago
8 0
Stop playing around amd start paying attention in class STUPID KIDS 
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-6y + 3(12y) = 20(y - 1) + 15 is it true?
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Answer:

y= - 1/2 (negative half) =  -0.5

Step-by-step explanation:

−6y+3(12y)=20(y−1)+15

Multiply 3 and 12 to get 36.

−6y+36y=20(y−1)+15

Combine −6y and 36y to get 30y.

30y=20(y−1)+15

Use the distributive property to multiply 20 by y−1.

30y=20y−20+15

Add −20 and 15 to get −5.

30y=20y−5

Subtract 20y from both sides.

30y−20y=−5

Combine 30y and −20y to get 10y.

10y=−5

Divide both sides by 10

y= -5/10

Reduce the fraction -5/10 = -0.5 to lowest terms by extracting and cancelling out 5 .

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X=a-2by(2) make y the subject
sladkih [1.3K]

Answer:

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y = √{(a - x)/2b}

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