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castortr0y [4]
2 years ago
8

Flowgorithm, Design a program that prompts the user to enter a number within the range of 1 through 10. The program should displ

ay the Roman numeral version of that number. If the number is outside the range of 1 through 10, the program should display an error message?

Computers and Technology
1 answer:
kherson [118]2 years ago
6 0

Answer:

Step by step code along with explanation and output is given below

Explanation:

We can solve this problem using if elif else approach

def main():

# prompts the user to enter an integer from 1 to 10

 num = int (input('Enter a number in the range of 1 to 10:\n'))

# using the if elif print out the roman numeral from 1 to 10

 if num == 1:

   print ('Roman Numeral for 1 is I')

 elif num == 2:

   print ('Roman Numeral for 2 is II')

 elif num == 3:

   print ('Roman Numeral for 3 is III')

 elif num == 4:

   print ('Roman Numeral for 4 is IV')

 elif num == 5:

   print ('Roman Numeral for 5 is V')

 elif num == 6:

   print ('Roman Numeral for 6 is VI')

 elif num == 7:

   print ('Roman Numeral for 7 is VII')

 elif num == 8:

   print ('Roman Numeral for 8 is VIII')

 elif num == 9:

   print ('Roman Numeral for 9 is IX')

 elif num == 10:

   print ('Roman Numeral for 10 is X')

# using the else print out error message whenever user enters any other number not listed above

 else:

   print ('Error! Wrong Input')

# call the main function

main()

Output:

Enter a number in the range of 1 to 10:

6

Roman Numeral for 6 is VI

Enter a number in the range of 1 to 10:

15

Error! Wrong Input

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Answer:

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Explanation:

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Match each logical function with its description. AND COUNTIF SUMIF IF tests for a certain condition and returns one of two valu
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1. IF
2. AND
3. COUNTIF
4. SUMIF
4 0
2 years ago
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adelina 88 [10]

Answer:

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Explanation:

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2 years ago
In cell M2, enter a formula using a nested IF function as follows to determine first if a student has already been elected to of
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Answer:

Following are the code to this question:

code:

=IF(EXACT(I2,"Yes"),"Elected",IF(EXACT(K2,"Yes"),"Yes","No"))

Explanation:

In the given the data is not defined so we explain only  the above code, but before that, we briefly define working of if the function that can be defined as follows:

  • The If() function, is used only when one of the logical functions and its value must return the value true. or we can say it only return a true value.
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8 0
2 years ago
A variable like user_num can store a value like an integer. Extend the given program as indicated. Output the user's input. (2 p
lapo4ka [179]

Answer:

The answer to this question is given below in the explanation section. It is noted that this program is written in C++ using online C++ compiler.

Explanation:

#include <iostream>

using namespace std;

int squared(int num)// this is the function to compute square

   {

       return num*num;

   }

int cube(int num)// this is the function to compute cube

   {

       return num*num*num;

   }

int main()

{

   int user_num, user_num2; // variable declaration

   

       cout<<"Enter the first number: ";//prompt user to enter the number

       cin>>user_num;//store the user entered number into variable

       cout<<"\nEnter the second number: ";//prompt the user to enter the second number

       cin>>user_num2;//store the user entered number into variable

   

   

   cout<<"\nSquared of first number is: "<<squared(user_num);//compute square of user_num and display

   cout<<"\nCube of first number is: "<<cube(user_num);//compute the cube of the user_num and display

   cout<<"\nSquare of second number is: "<<squared(user_num2);//compute the square of user_num2 and display

   cout<<"\nCube of second number is: "<<cube(user_num2);//compute the cube of user_num2 and display

   

   cout<<"\nSum of number 1 and number 2 is: "<<user_num2 + user_num2;//display the sum of user_num2 and user_num

   cout<<"\nProduct of number 1 and number 2 is: "<<user_num2 * user_num;//display the product of user_num and user_num2

   

   

   return 0;//terminate the program

}

                               

7 0
2 years ago
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