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andreev551 [17]
1 year ago
9

Take the following list of functions and arrange them in ascending order of growth rate. That is, if function g(n) immediately f

ollows function f(n) in your list, then it should be the case that f(n) is O(g(n)). g1(n) = 2√log n g2(n) = 2n g4(n) = n4/3 g3(n) = n(log n)3 g5(n) = n logn g6(n) = 2^(2^n ) g7(n) = 2^(n^2 )
Mathematics
1 answer:
zepelin [54]1 year ago
4 0

Answer:

Step-by-step explanation:

From order of growth rate ; Constant < Logarithmic < Polynomial < Exponential

Hence in ascending order ; n (log n)³ < n^4/3 < n^log n < 2√^(logn) < 2n < 2n² < 2^2n

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Emerson purchased a game that was on sale for 18% off. The sales tax in his county is 8%. Let y represent the original price of
leva [86]

Answer:

y(.82)*1.08

Step-by-step explanation:

You multiply by .82 to get the cost of the game after the discount and then by 1.08 to add the tax and total amount.  

6 0
1 year ago
Read 2 more answers
Jody bought 20 shares of amazon at the close price of $121.00. She bought 20 more shares a year later at the price of $127.00. T
hjlf

Answer:

Jody made $210 after all of these transactions.

Step-by-step explanation:

Jody bought 20 shares of amazon at the price of $121.00

= 121.00 × 20 = $2,420

After one year she bought 20 more shares at the price of $127.00

= 127.00 × 20 = $2,540

Her broker charges $50.00 for each transaction = 50 × 2 = $100

Total cost of all shares = 2,420 + 2,540 + 100 = $5,060

She sold all of her shares at the price of $133.00

= 133 × 40 = $5,320

She gave broker charge for this transaction = $50.00

Total selling amount  = 5,320 - 50 = $5,270

Profit = Selling amount - cost

Profit = 5,270 - 5,060 = $210

Jody made $210 after all of these transactions.

8 0
1 year ago
Read 2 more answers
Yu, Nailah, and Elena each bought between 7 and 9 yards of ribbon. Yu bought 3 pieces of ribbon. Nailah bought 5 pieces of ribbo
Svetllana [295]

ENter you name for more info:________________

5 0
2 years ago
The most popular mathematician in the world is throwing aparty for all of his friends. As a way to kick things off, they decidet
ratelena [41]

Answer:

The no. of possible handshakes takes place are 45.

Step-by-step explanation:

Given : There are 10 people in the party .

To Find: Assuming all 10 people at the party each shake hands with every other person (but not themselves, obviously) exactly once, how many handshakes take place?

Solution:

We are given that there are 10 people in the party

No. of people involved in one handshake = 2

To find the no. of possible handshakes between 10 people we will use combination over here

Formula : ^nC_r=\frac{n!}{r!(n-r)!}

n = 10

r= 2

Substitute the values in the formula

^{10}C_{2}=\frac{10!}{2!(10-2)!}

^{10}C_{2}=\frac{10!}{2!(8)!}

^{10}C_{2}=\frac{10 \times 9 \times 8!}{2!(8)!}

^{10}C_{2}=\frac{10 \times 9 }{2 \times 1}

^{10}C_{2}=45

No. of possible handshakes are 45

Hence The no. of possible handshakes takes place are 45.

4 0
1 year ago
You deposit $300 in a savings account that pays 6% interest compounded semiannually. How much will you have at the middle of the
Makovka662 [10]

Answer:

  • The total amount accrued, principal plus interest,  from compound interest on an original principal of  $ 300.00 at a rate of 6% per year  compounded 2 times per year  over 0.5 years is $ 309.00.

  • The total amount accrued, principal plus interest,  from compound interest on an original principal of  $ 300.00 at a rate of 6% per year  compounded 2 times per year  over 1 year is $ 318.27.

Step-by-step explanation:

a)  How much will you have at the middle of the first year?

Using the formula

A\:=\:P\left(1+\frac{r}{n}\right)^{nt}

where

  • Principle = P
  • Annual rate = r
  • Compound = n
  • Time  = (t in years)
  • A = Total amount

Given:

Principle P = $300

Annual rate r = 6% = 0.06 per year

Compound n = Semi-Annually = 2

Time (t in years) = 0.5 years

To determine:

Total amount = A = ?

Using the formula

A\:=\:P\left(1+\frac{r}{n}\right)^{nt}

substituting the values

A=300\left(1+\frac{0.06}{2}\right)^{\left(2\right)\left(0.5\right)}

A=300\cdot \frac{2.06}{2}

A=\frac{618}{2}

A=309 $

Therefore, the total amount accrued, principal plus interest,  from compound interest on an original principal of  $ 300.00 at a rate of 6% per year  compounded 2 times per year  over 0.5 years is $ 309.00.

Part b) How much at the end of one year?

Using the formula

A\:=\:P\left(1+\frac{r}{n}\right)^{nt}

where

  • Principle = P
  • Annual rate = r
  • Compound = n
  • Time  = (t in years)
  • A = Total amount

Given:

Principle P = $300

Annual rate r = 6% = 0.06 per year

Compound n = Semi-Annually = 2

Time (t in years) = 1 years

To determine:

Total amount = A = ?

so using the formula

A\:=\:P\left(1+\frac{r}{n}\right)^{nt}

so substituting the values

A\:=\:300\left(1+\frac{0.06}{2}\right)^{\left(2\right)\left(1\right)}

A=300\cdot \frac{2.06^2}{2^2}

A=318.27 $

Therefore, the total amount accrued, principal plus interest,  from compound interest on an original principal of  $ 300.00 at a rate of 6% per year  compounded 2 times per year  over 1 year is $ 318.27.

3 0
1 year ago
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