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slavikrds [6]
2 years ago
13

The human resource department at a certain company wants to conduct a survey regarding worker benefits. The department has an al

phabetical list of all 4247 employees at the company and wants to conduct a systematic sample of size 40 (a) What is k? k- 106 (b) Determine the individuals who will be administered the survey. Randomly select a number from 1 to k. Suppose that we randomly select 19. Starting with the first individual selected, the individuals in the survey will be 19. 125 231
Mathematics
1 answer:
dezoksy [38]2 years ago
3 0

Answer:

Step-by-step explanation:

Hello!

A systematic sample is a sampling type where, the population units are listed in a certain order, the first unit is randomly chosen from the first k number of units and then the subsequent units are selected in intervals of k. To calculate k, in case you know the population size, you have to divide the population size by the sample size (usually established based on previous information. Remember k is always a whole number.

a) k= pob/n= 4247/40= 106.175 ≅ 106

b) From the 106 individuals you have to randomly select the first unit. Then starting from it the next 39 individuals surveyed will be the +k

Using a random number calculator I've chosen the first individual to be surveyed as number 57 after that you have to add k= 106 to know wich are the next individuals to be sampled:

1) 57                          11) 1117        21) 2177       31) 3237

2) 57 + 106= 163      12) 1223      22) 2283    32) 3343

3) 269                      13) 1329      23) 2389     33) 3449

4) 375                       14) 1435      24) 2495     34) 3555

5) 481                        15) 1541       25) 2601     35) 3661

6) 587                       16) 1647      26) 2707     36) 3767

7) 693                       17) 1753       27) 2813      37) 3873

8) 799                       18) 1859       28) 2919     38) 3979

9) 905                       19) 1965       29) 3025    39) 4085

10) 1011                      20) 2071       30) 3131      40) 4191

I hope it helps!

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Let P2 be the vector space of all polynomials of degree 2 or less, and let H be the subspace spanned by 10x2+4xâ1, 3xâ4x2+3, and
lord [1]

I suppose

H=\mathrm{span}\{10x^2+4x-1,3x-4x^2+3,5x^2+x-1\}

The vectors that span H form a basis for P_2 if they are (1) linearly independent and (2) any vector in P_2 can be expressed as a linear combination of those vectors (i.e. they span P_2).

  • Independence:

Compute the Wronskian determinant:

\begin{vmatrix}10x^2+4x-1&3x-4x^2+3&5x^2+x-1\\20x+4&3-8x&10x+1\\20&-8&10\end{vmatrix}=-6\neq0

The determinant is non-zero, so the vectors are linearly independent. For this reason, we also know the dimension of H is 3.

  • Span:

Write an arbitrary vector in P_2 as ax^2+bx+c. Then the given vectors span P_2 if there is always a choice of scalars k_1,k_2,k_3 such that

k_1(10x^2+4x-1)+k_2(3x-4x^2+3)+k_3(5x^2+x-1)=ax^2+bx+c

which is equivalent to the system

\begin{bmatrix}10&-4&5\\4&3&1\\-1&3&-1\end{bmatrix}\begin{bmatrix}k_1\\k_2\\k_3\end{bmatrix}=\begin{bmatrix}a\\b\\c\end{bmatrix}

The coefficient matrix is non-singular, so it has an inverse. Multiplying both sides by that inverse gives

\begin{bmatrix}k_1\\k_2\\k_3\end{bmatrix}=\begin{bmatrix}-\dfrac{6a-11b+19c}3\\\dfrac{3a-5b+2c}3\\\dfrac{15a-26b+46c}3\end{bmatrix}

so the vectors do span P_2.

The vectors comprising H form a basis for it because they are linearly independent.

4 0
2 years ago
You and three friends own a paint shop. The shop's profit was $536 in the first month. You always divide the profits equally. In
alexandr1967 [171]
C.  $360


$224x4=896 (total profit)

$896 (total) - $536 (first month profit) = $360 (second month profit)
4 0
2 years ago
Read 2 more answers
A poll conducted a week before the school election to the student council showed that Janice would win with 63% of the vote. The
k0ka [10]

OPTIONS:

No, because she could receive as low as 14% of the vote.

No, because she could receive as low as 49% of the vote.

Yes, because she could receive as much as 77% of the vote.

Yes, because the poll stated that she will win with 63% of the vote.

Answer:

No, because she could receive as low as 49% of the vote.

Step-by-step explanation:

Given that:

Poll suggestion = 63%

Margin of Error (E) = 14%

This means that; the range or interval in which the vote obtained could fall would be ;

Poll suggestion ± margin of Error

63% ± 14%

Lower bound attainable = (63% - 14%) = 49%

Upper bound attainable = (63% + 14%) = 77%

Since, winning actually requires obtaining atleast half of the votes (that is 50%) ; and suggested poll suggested votes could fall as low as 49% ; then Janice can't be so confident of victory.

8 0
2 years ago
During the 2015-16 NBA season, J.J. Redick of the Los Angeles Clippers had a free throw shooting percentage of 0.901 . Assume th
ser-zykov [4K]

Answer: 0.5898

Step-by-step explanation:

Given :  J.J. Redick of the Los Angeles Clippers had a free throw shooting percentage of 0.901 .

We assume that,

The probability that .J. Redick makes any given free throw =0.901  (1)

Free throws are independent.

So it is a binomial distribution .

Using binomial probability formula, the probability of getting success in x trials :

P(X=x)^nC_xp^x(1-p)^{n-x}

, where n= total trials

p= probability of getting in each trial.

Let x be binomial variable that represents the number of a=makes.

n= 14

p= 0.901     (from (1))

The probability that he makes at least 13 of them will be :-

P(x\geq13)=P(x=13)+P(x=14)

=^{14}C_{13}(0.901)^{13}(1-0.901)^1+^{14}C_{14}(0.901)^{14}(1-0.901)^0\\\\=(14)(0.901)^{13}(0.099)+(1)(0.901)^{14}\ \ [\because\ ^nC_n=1\ \&\ ^nC_{n-1}=n ]\\\\\approx0.3574+0.2324=0.5898

∴ The required probability = 0.5898

5 0
2 years ago
Exams are approaching and Helen is allocating time to studying for exams. She feels that with the appropriate amount of studying
svp [43]

Answer: 0.05

Step-by-step explanation:

Let M = Event of getting an A in Marketing class.

S = Event of getting an A in Spanish class,

i.e. P(M) = 0.80 , P(S) = 0.60 and P(M∩S)=0.45

Required probability = P(neither M nor S)

= P(M'∩S')

= P(M∪S)'                                 [∵P(A'∩B')=P(A∪B)']

=1- P(M∪S)                               [∵P(A')=1-P(A)]

= 1- (P(M)+P(S)- P(M∩S))   [∵P(A∪B)=P(A)+P(B)-P(A∩B)]

= 1- (0.80+0.60-0.45)

= 1- 0.95

= 0.05

hence, the probability that Helen does not get an A in either class= 0.05

3 0
2 years ago
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