Question

A biochemist carefully measures the molarity of glycerol in 913 mL of photobacterium cell growth medium to be 81.3 μM.

Answer 1

Answer : The new molarity of glycerol in the photobacterium cell growth medium is, $6.69\times 10^3\mu M$

Explanation :

Formula used :

$M_1V_1=M_2V_2$

where,

$M_1\text{ and }V_1$ are the initial molarity and volume of glycerol.

$M_2\text{ and }V_2$ are the new molarity and volume of glycerol .

We are given:

$M_1=81.3\mu M\\V_1=913mL\\M_2=?\\V_2=11.1mL$

Putting values in above equation, we get:

$81.3\mu M\times 913mL=M_2\times 11.1mL\\\\M_2=6.69\times 10^3\mu M$

Hence, the new molarity of glycerol in the photobacterium cell growth medium is, $6.69\times 10^3\mu M$