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fomenos
2 years ago
10

Ram can complete the work in 10 hours, Ajit in 12 hours and Suresh in 15 hours. All of them began the work together, but Ram had

to leave the work after 2 hours of the start and Ajit left 3 hours before the completion of the work. How long did the work last? Select one:
a. 7 hrs
b. 8 hrs
c. 9 hrs
d. Cannot be determined
Mathematics
2 answers:
zmey [24]2 years ago
8 0
D. Because Ram only did 2 hours so then that makes 2 hours of work done but then left for whatever reason. Ajit left 3 hours BEFORE the completion of the work and that gives us info that there were hours put in between both Rams and Ajits work. They all started at the same time so it doesn't mean that Ajit didn't do any of the work. Ajit can work for 12 hours POSSIBLY. It did not say he can exact. So it leaves to Suresh that can work up to 15 hours of the work but we dont know how long he did it. Suresh either could just gone over or less than 15 hours. 

If this answer was way out of the question then i am sorry and i probably was wrong. 
adell [148]2 years ago
4 0

Answer:

Option A is the correct answer.

Step-by-step explanation:

Let the work be W.

Ram can complete the work in 10 hours, Ajit in 12 hours and Suresh in 15 hours.

\texttt{Rate of Ram =}\frac{W}{10}\\\\\texttt{Rate of Ajit =}\frac{W}{12}\\\\\texttt{Rate of Suresh =}\frac{W}{15}

Ram had to leave the work after 2 hours of the start and Ajit left 3 hours before the completion of the work.

Let t be the time of work completion,

We have

              W=2\times \frac{W}{10}+(t-3)\times \frac{W}{12}+t\times \frac{W}{15}\\\\1=\frac{1}{5}+\frac{t-3}{12}+\frac{t}{15}\\\\12+5(t-3)+4t=60\\\\9t=63\\\\t=7hours

Option A is the correct answer.

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the points A (1, 5), B (5, 5) and C (5, 1) are 3 corners of a square ABCD. what are the coordinates of D, the 4th corner
bogdanovich [222]

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(1,1)

This is the answer

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2 years ago
an employer will do a 50% match on your investment to a 401k retirement plan. If you decide to contribute a monthly amount of $2
faltersainse [42]

Answer:

The amount that should be in the account after 15 years is $95,321.85

Step-by-step explanation:

According to the given data, we have the following:

monthly amount of $220=R

interest rate is fixed at 2.05%. We require the monthly ineterest rate, hence monthly interest rate= 2.05%/12=0.1708%=0.0017

t=15years×12=180 months

In order to calculate how much should be in the account after 15 years, we would have to use the following formula:

Ap=<u>R(1-(1+i)∧-t)</u>

             i

Ap=<u>220(1-(1+0.0017)∧-180)</u>

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Ap=<u>162,04</u>

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Ap=$95,321.85

The amount that should be in the account after 15 years is $95,321.85

<u />

6 0
2 years ago
The mass of a stone is 5kg. The stone is twice as heavy as a book. The book is 5 times heavier than a ball. What is the mass of
Irina18 [472]
The answer is 1.01 I did it on paper
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2 years ago
Last year Beth's annual salary was $38,350. This year she received a promotion and now earns $46,462 annually. She is paid biwee
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Answer:

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8 0
1 year ago
A circular platform is to be built in a playground. The center of the structure is required to be equidistant from three support
castortr0y [4]

Answer:

The coordinates for the location of the center of the platform are (0, 1)

Step-by-step explanation:

The equation of the circle of center (h , k) and radius r is:

(x - h)² + (y - k)² = r²

Now,

- The center is equidistant from any point lies on the circumference of the circle

- There are three points equidistant from the center of the circle

- We have three unknowns in the equation of the circle h , k , r

Thus, let's substitute the coordinates of these point in the equation of the circle to find h , k , r.

The equation of the circle is (x - h)² + (y - k)² = r²

∵ Points A(2,−3), B(4,3), and C(−2,5)

- Substitute the values of x and y the coordinates of these points

Point A (2 , -3)

(2 - h)² + (-3 - k)² = r² - - - (1)

Point B (4 , 3)

(4 - h)² + (3 - k)² = r² - - - - (2)

Point C (-2 , 5)

(-2 - h)² + (5 - k)² = r² - - - - (3)

- To find h , k equate equation (1) and (2) and same for equation (2) and (3) because all of them equal r²

Thus;

(2 - h)² + (-3 - k)² = (4 - h)² + (3 - k)² - - - - - (4)

(4 - h)² + (3 - k)² = (-2 - h)² + (5 - k)² - - - - -(5)

- Simplify (5);

h² - 8h + 16 + k² - 6k + 9 = h² + 4h + 4 + k² - 10k + 25

h² and k² will cancel out to give;

-8h - 6k + 25 = 4h - 10k + 29

Rearranging, we have;

12h - 4k = -4 - - - - (6)

Similarly, for equation 4;

(2 - h)² + (-3 - k)² = (4 - h)² + (3 - k)²

h² - 4h + 4 + k² + 6k + 9 = h² - 8h + 16 + k² - 6k + 9

h², k² and 9 will cancel out to give;

4 - 4h + 6k = 16 - 8h - 6k

Rearranging;

4h + 12k = 12 - - - - (7)

Divide by 4 to give;

h + 3k = 3

Making h the subject;

h = 3 - 3k

Put 3 - 3k for h in eq 6;

12(3 - 3k) - 4k = -4

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k = 40/40

k = 1

h = 3 - 3(1)

h = 0

The coordinates for the location of the center of the platform are (0, 1)

5 0
2 years ago
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