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Juli2301 [7.4K]
2 years ago
11

A food truck operator has traditionally sold 75 bowls of noodle soup each day. He moves to a new location and after a week sees

that he has averaged 85 bowls of noodle soup sales each day. He runs a one-sided hypothesis test to determine if his daily sales at the new location have increased. The p-value of the test is 0.031. How should he interpret the p-value?
a. There is a 3.1% chance that the true mean of soup sales at the new location is 85 bowls a day.
b. There is a 96.9% chance that the true mean of soup sales at the new location is greater than 75 bowls a day.
c. There is a 96.9% chance that the sample mean of soup sales at the new location is 85 bowls a day.
d. There is a 3.1% chance of obtaining a sample with a mean of 85 or higher assuming that the true mean sales at the new location is still equal to or less than 75 bowls a day.
e. There is a 96.9% chance that the true mean of soup sales at the new location is within 3.1 bowls of 85 bowls a day.
Mathematics
1 answer:
pashok25 [27]2 years ago
7 0

Answer:

The p-value of the test is 0.031. How should he interpret the p-value as "There is a 96.9% chance that the true mean of soup sales at the new location is greater than 75 bowls a day"

Step-by-step explanation:

P-value"In statistical hypothesis testing, the p-value or probability value is the probability of obtaining test results at least as extreme as the results actually observed during the test, assuming that the null hypothesis is correct"

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Find the sum of the first 63 terms of –19, -13, -7 …
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We know that Common difference is Difference of second term and first term.

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We know that Sum of n terms is given by : S_n = \frac{n}{2}(2a + (n - 1)d)

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Step-by-step explanation:

I hope this help.

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