A 12-kN tensile load will be applied to a 50-m length of steel wire with E = 200 GPa. Determine the smallest diameter wire that
1 answer:
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Answer:
Temperature at center of apples = 11.2⁰C
Temperature at surface of apples = 2.7⁰C
Amount of Heat transferred = 17.2kJ
Explanation:
The properties of apple are given as:
k = 0.418 W/m.°C
ρ = 840 kg/m³
Cр = 3.81 kJ/kg.°C
α = 1.3*10 ⁻⁷ m²/s
h = 8 W/m².°C
d = 0.09m
r = 0.045m
t = 1 hour = 3600s
<h2>Solution</h2>Biot number is given as:
The constants λ₁ and A₁ corresponding to Biot number (from the table) are:
λ₁ = 1.476
A₁ = 1.239
Fourier Number is:
As Fourier Number > 0.2 , one term approximates solutions are applicable
The temperature at the center of apples, The temperature at surface of apples and Amount of heat transfer is found in the ATTACHMENT.
Answer:
% reduction in area==PR=0.734=73.4%
% elongation=EL=0.42=42%
Explanation:
given do=12.8 mm
df=6.60
Lf=72.4 mm
Lo=50.8 mm
% reduction in area=((*(do/2)^2)-(
*(df/2)^2)))/
*(do/2)^2
substitute values
% reduction in area=73.4%
% elongation=EL=((Lf-Lo)/Lo))*100
% elongation=((72.4-50. 8)/50.8)*100=42%