All categories

1 year ago

The circumference of a tire is 96 inches. Determine the radius of the tire use 3 for pie

Mathematics

1 answer:

masya89 [10]1 year ago

7 0

Circumference = 2*pi*radius.

Pi = 3.

2 * pi * r = 96

2 * 3 = 6.

2 * 3 * r = 96

Find r: 96/6 = 16.

2 * 3 *16 = 96.

r = 16.

You might be interested in

Find the value of x in each case:

Zanzabum

Answer:

$x=30\°$

Step-by-step explanation:

<u>Find the measures of interior angles in each triangle</u>

Triangle BGC

$m$

The measures of triangle BGC are $90\°-60\°-30\°$

Triangle CGH

we know that

$m$ -----> by consecutive interior angles

we have that

$m$

substitute

$m$

we have

$m$

remember that

$m$

$60\°+2x+180\°-4x=180\°$

$60\°=2x$

$x=30\°$

The measures of triangle CGH are $60\°-60\°-60\°$

Triangle GHE

$m< EGH=90\°-2x=90-2(30\°)=30\°$

$m< GHE=4x=4(30\°)=120\°$

remember that

$m$

substitute and solve for m<GEH

$30\°+120\°+m$

$150\°+m$

$m$

The measures of triangle GHE are $30\°-120\°-30\°$

6 0

2 years ago

Read 2 more answers

Theresa has hired Chuck and Diana to paint a fence. Diana can paint 150 fence posts in the same time it takes Chuck to paint 130

Alenkasestr [34]

Answer: Chuck can paint 65 posts per hour.

Step-by-step explanation:

The data we have here is:

Diana can paint 150 fence posts in a time T

Chuck can pint 130 fence posts in a time T.

In one hour, Diana can paint 10 more fence posts than Chuck.

If D is the hourly rate of Daian, and C is the hourly rate for Chuck, we have:

D = 150/T

C = 130/T

D = C + 10

we can replace the last equation in the first one and geT:

C + 10 =150/T

C = 130/T

Now we can replace the bottom equation in the above one:

130/T + 10 = 150/T

10 = 150/T - 130/T = 20/T

T*10 = 20

T = 20/10 = 2

So T is 2 hours, then whe have:

D = 150post/2hours = 75 posts per hour.

C = 130 posts/2hours = 65 posts per hour.

4 0

2 years ago

Consider the initial value problem y′+4y=48t,y(0)=9. y′+4y=48t,y(0)=9. Take the Laplace transform of both sides of the given dif

Nadusha1986 [10]

Answer:

$sY(s)-y(0) +4Y(s) = 48 *\frac{1}{s^2}$

Step-by-step explanation:

given is the Differential equation in I order linear as

$y′+4y=48t,y(0)=9.$

Take Laplace on both sides

$L(y') +4L(y) = 48L(t)\\sY(s)-y(0) +4Y(s) = 48 *\frac{1}{s^2} \\Y(s) [s+4]=\frac{48}{s^2}+9\\Y(s) = \frac{1}{s^2(s+4)}+\frac{9}{s+4}$

Now if we take inverse we get y(t) the solution

Thus the algebraic equation would be $sY(s)-y(0) +4Y(s) = 48 *\frac{1}{s^2}$

8 0

1 year ago

Isiah just accepted a job that pays an annual salary of $48,800 and was promised a 7.75% raise per year for the next five years

e-lub [12.9K]

Answer:

Umm higher than the salary

6 0

2 years ago

What is the ratio of the area of sector ABC to the area of sector DBE?

shusha [124]

We have to find the" ratio of the area of sector ABC to the area of sector DBE".

Now,

the general formula for the area of sector is

Area of sector= 1/2 r²θ

where r is the radius and θ is the central angle in radian.

180°= π rad

1° = π/180 rad

For sector ABC, area= 1/2 (2r)²(β°)

= 1/2 *4r²*(π/180 β)

= 2r²(π/180 β)

For sector DBE, area= 1/2 (r)²(3β°)

= 1/2 *r²*3(π/180 β)

= 3/2 r²(π/180 β)

Now ratio,

Area of sector ABC/Area of sector DBE = $\frac{2r^{2}*\ \frac{\pi}{180} beta}{3/2 r^{2}*\ \frac{\pi}{180}beta}$

= 4/3

7 0

2 years ago

Read 2 more answers