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Ronch [10]
2 years ago
4

Erik took a trip to see his friend Mike who lives 308 miles away. He left his place at 10 AM driving at 70 mph. In 2 hours, his

friend Mike left his place driving towards Erik at an average speed of 50 mph. At what time will they meet?
Mathematics
1 answer:
barxatty [35]2 years ago
3 0

Answer:

<u>Erik and Mike will meet at 1:24 PM</u>

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

Distance between Erik and Mike = 308 miles

Speed that Erik drove = 70 mph

Time Erik left = 10 AM

Speed that Mike drove = 50 mph

Time Mike left = 12 PM

2. At what time will they meet?

For answering the question, let's find how much miles Erik drove at 12 PM, when Mike started to drive towards Erik:

Miles driven by Erik after two hours = Speed * Time

Miles driven by Erik after two hours = 70 * 2

Miles driven by Erik after two hours = 140

Now we can calculate the distance between Erik and Mike at 12 PM, this way:

308 - 140 = 168

At 12 PM the distance between Erik and Mike is 168 miles

t = time it takes Erik and Mike to meet

The equation to solve for t is:

Distance Erik will travel = 70t

Distance Mike will travel = 50t

70t + 50t = 168

120t = 168

t = 168/120

t = 1.4 hours

1.4 hours = 1 hour + 4/10 * 60 minutes = 1 hour + 24 minutes

Time of the day Erik and Mike will meet = 12 PM + 1 hour and 24 minutes

<u>Time of the day Erik and Mike will meet = 1:24 PM</u>

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Answer:

C. x² − 8x + 24 − 72/(x+3)

Step-by-step explanation:

See attached picture for long division method.

Logically, we know x³ − 5x² factors to x² (x − 5).  Since x + 3 isn't a factor, we know the remainder isn't 0.  So we can narrow the options down to A or C.

One way to find the remainder is through long division.  Or, since this is multiple choice, we multiply the options by x + 3 and see which one results in an answer of x³ − 5x².

(x + 3) (x² − 8x + 24 − 72/(x+3))

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2 years ago
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Answer:

D. There is not enough evidence at the 5% significance level to indicate that one route gets Katy to work faster, on average, since 0 falls within the bounds of the confidence interval.

Step-by-step explanation:

At 5% confidence level, Katy found difference in mean commuting times (Route 1-Route 2) in minutes as (-1,9).

Since no difference in means (0 min) falls within the confidence level (-1,9), we can not reject the hypothesis that there is no difference in mean commuting times when using Route1 or Route2.

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All angles add up to the same degree
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1/3 is the one portion of total distance.

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i like your pfp btw <33

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