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zheka24 [161]
2 years ago
3

A city's water supply is contaminated with a toxin at a concentration of 0.63 mg/L. Fortunately, this toxin decomposes to a safe

mixture of products by first-order kinetics with a rate constant of 0.27 day–1. How long will it take for half of the toxin to decompose?
Chemistry
1 answer:
Svetradugi [14.3K]2 years ago
3 0

Answer:

t = 2,57 days

Explanation:

A reaction follows the first-order kinetics when attend the formula:

ln\frac{[A]_t}{[A]_0} = -kt

Where [A]₀ is the initial concentration of the toxin (0,63mg/L) and [A]t is the half of the initial concentration (0,315mg/L). k is 0,27 day⁻¹ and t is the time the descomposition takes. Replacing:

ln\frac{0,315}{0,63} = -0,27day^{-1}t

<em>t = 2,57 days</em>

<em></em>

I hope it helps!

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For the reaction of oxygen and nitrogen to form nitric oxide, consider the following thermodynamic data (Due to variations in th
CaHeK987 [17]

Answer:

a. 7278 K

b. 4.542 × 10⁻³¹

Explanation:

a.

Let´s consider the following reaction.

N₂(g) + O₂(g) ⇄ 2 NO(g)

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Combining [1] and [2],

ΔH° - T × ΔS° < 0

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b.

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7 0
2 years ago
If 25.0 g of NH₃ and 45.0g of O₂ react in the following reaction, what is the mass in grams of NO that will be formed? 4 NH₃ (g)
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Answer:

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n (O2)=(45.0 g)/(32 g/mol)

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