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Xelga [282]
2 years ago
3

Assume that there are about 400 students in your class. If every student is to be assigned a unique bit pattern, a. What is the

minimum number of bits required to do this? b. How many more students can be admitted to the class without requiring additional bits for each student's unique bit pattern?
Mathematics
1 answer:
Fiesta28 [93]2 years ago
7 0

Answer: a. 256 bits and b. 56 students

Step-by-step explanation:

Bit is a combination of 0 and 1

each byte contains 8 bit, so each student need 8 bits to assigned him a unique pattern

Zeros and ones means binary

Therefore 2^n

= 2^8

=256 bits

(b)

The number of students that can be admitted without additionl bit will be:

= 256 - 200

= 56 students

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P(R\ and\ B) = 0.0256

Step-by-step explanation:

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Required

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P(R\ and\ B) = P(R)\ and\ P(B)

This is then solved further as:

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