Answer:
78
Step-by-step explanation:
Smallest square: 1
Small Square: 2, Area of 4
Mid Square: 3, Area of 9
Mid White Square: 5, Area of 25
Big Square: 8, Area of 64
1 + 4 + 9 + 64 = 78
Answer:
0.0045 = 0.45% probability that less than two of them ended in a divorce
Step-by-step explanation:
For each marriage, there are only two possible outcomes. Either it ended in divorce, or it did not. The probability of a marriage ending in divorce is independent of any other marriage. This means that the binomial probability distribution is used to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which
is the number of different combinations of x objects from a set of n elements, given by the following formula.

And p is the probability of X happening.
55% of marriages in the state of California end in divorce within the first 15 years.
This means that 
Suppose 10 marriages are randomly selected.
This means that 
What is the probability that less than two of them ended in a divorce?
This is

In which




0.0045 = 0.45% probability that less than two of them ended in a divorce
Answer:
20.33%
Step-by-step explanation:
We have that the mean (m) is equal to 87.5, the standard deviation (sd) 6.25 and the sample size (n) = 12
They ask us for P (x <86)
For this, the first thing is to calculate z, which is given by the following equation:
z = (x - m) / (sd / (n ^ 1/2))
We have all these values, replacing we have:
z = (86 - 87.5) / (6.25 / (12 ^ 1/2))
z = -0.83
With the normal distribution table (attached), we have that at that value, the probability is:
P (z <-0.83) = 0.2033
The probability is 20.33%
Answer:
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