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vladimir1956 [14]
2 years ago
4

The density of liquid carbon disulfide, CS2, is 1293 kg m–3. Calculate the change in the molar Gibbs energy of carbon disulfide

when it is compressed by a change in pressure from 1.00 bar to 4.00 bar.
Chemistry
1 answer:
vovikov84 [41]2 years ago
4 0

Answer:

The change in the molar Gibbs energy of carbon disulfide is 1102.31 kJ/mol.

Explanation:

∆G = ∆H - T∆S

Using the steam table,

At 1 bar,

T1 = 99.6°C

H1 = 417 kJ/kg

S1 = 1.303 kJ/kg.K

At 4 bar,

T2 = 143.6°C

H2 = 605 kJ/kg

S2 = 1.776 kJ/kg.K

T = T2 - T1 = 143.6 - 99.6 = 44°C = 44+273 = 317 K

∆H = H2 - H1 = 605 - 417 = 188 kJ/kg

∆S = S2 - S1 = 1.776 - 1.303 = 0.473 kJ/kg.K

∆G = 188 - 317(0.473) = 188 - 149.941 = 38.059 kJ/kg

Density of CS2 = 1293 kg/m^3

Molar volume = 0.0224 m^3/mol

Change in molar Gibbs energy of CS2 = ∆G × density × molar volume = 38.059 kJ/kg × 1293 kg/m^3 × 0.0224 m^3/mol = 1102.31 kJ/mol

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Answer:

B, E, & G

Oxygen, Argon, & Carbon

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2 years ago
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3. From the following formula, calculate the quantities required to make 5 lb o hydrophilic ointment. Methylparaben 0.25 g Propy
adell [148]

The given question is incomplete. The complete question is as follows.

From the following formula, calculate the quantities required for each of the following ingredients to make 5 lb. (avoir) of hydrophilic ointment. All values to be in g, do not include units in your submitted answer; use no more than 3 decimal places. Convert using 1 lb = 454 g. Note: all values done by mass, including the water, so this is not a q.s situation (volume is irrelevant).

Methylparaben 0.25 g

Propylparaben 0.15 g

Sodium Lauryl Sulfate 10 g

Propylene Glycol 120 g

Stearyl Alcohol 240 g

White Petrolatum 250 g

Purified Water, to make 1000 g

Explanation:

For the given quantities, the sum is 620.4 g. Now, amount of purified water (to make 1000 g of ointment)  is as follows.

             1000 g - 620.4 g

           = 379.6 g

Now, to make 5 lb we will calculate the quantities as follows.

Formula weight = 1000 g

Therefore, desired quantity is as follows.

             5 lb = 5 x 454 g

                     = 2270 g

Hence, this means the factor is  calculated as follows.

       \frac{2270 g}{1000 g}

            = 2.27

Now, we will calculate the quantity of each ingredient using factor 2.27 as follows.

  • Methylparaben = 0.25 g x 2.27 = 0.5675 g
  • Propylparaben = 0.15 g x 2.27 = 0.3405 g
  • Sodium Lauryl Sulfate = 10 g x 2.27 = 22.7 g
  • Propylene Glycol = 120 g x 2.27 = 272.4 g
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  • White Petrolatum = 250 g x 2.27 = 567.5 g
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7 0
2 years ago
Three samples of gas each exert 740 mm hg in separate 2 L containers what pressure do they exert if they are all placed in a sin
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Answer:

P(total) = 1110 mmHg

Explanation:

According to the Dalton law of partial pressure,

The pressure exerted by mixture of gases are equal to the sum of partial pressure of individual gases.

P(total) = P1 + P2 + P3+ .....+ Pn

Given data:

Sample A = 740 mmHg

Sample B = 740 mmHg

Sample C = 740 mmHg

Total pressure = ?

Solution:

<em>Sample A:</em>

P₁V₁ = P₂V₂

P₂ = P₁V₁ / V₂

P₂ = 740 mmHg × 2L/4L

P₂ = 370 mmHg

<em>Sample B:</em>

P₁V₁ = P₂V₂

P₂ = P₁V₁ / V₂

P₂ = 740 mmHg × 2L/4L

P₂ = 370 mmHg

<em>Sample C:</em>

P₁V₁ = P₂V₂

P₂ = P₁V₁ / V₂

P₂ = 740 mmHg × 2L/4L

P₂ = 370 mmHg

Total pressure:

P(total) = P1 + P2 + P3

P(total) =  370 mmHg +  370 mmHg+  370 mmHg

P(total) = 1110 mmHg

6 0
2 years ago
Consider NH3 and PH3. Electronegativities: P = 2.1, H = 2.1, N=3.0. Which statement is false?
NikAS [45]

Answer:

The P-H bonds are more polar than the N-H bonds.

Explanation:

Phosphine is a polar molecule with non-polar bonds. The phosphorus atom is bonded to three hydrogen atoms and the phosphorus atom has a lone pair of electrons. Since hydrogen and phosphorus are equal in electronegativity, it implies that they attract the shared pairs of electrons the same amount,hence bonding electrons are shared equally making the covalent bonds non-polar.

The lone pair of electrons on phosphorus causes the molecule to be asymmetrical with respect to charge distribution this is why the molecule is polar even though the are non-polar bonds in the molecule.

Looking at the values of electro negativity stated in the question, one can easily see that the difference in electro negativity between nitrogen and hydrogen is 0.9 while the difference in electro negativity between phosphorus and hydrogen is zero. It is clear that NH3 is naturally more polar than PH3 since each individual N-H bond in NH3 is a polar bond while the individual P-H bonds in PH3 are nonpolar.

4 0
2 years ago
If 500.0 mL of 0.10 M Ca2+ is mixed with 500.0 mL of 0.10 M SO42−, what mass of calcium sulfate will precipitate? Ksp for CaSO4
statuscvo [17]

Answer:

The mass of calcium sulfate that will precipitate is 6.14 grams

Explanation:

<u>Step 1:</u> Data given

500.0 mL of 0.10 M Ca^2+ is mixed with 500.0 mL of 0.10 M SO4^2−

Ksp for CaSO4 is 2.40*10^−5

<u>Step 2:</u> Calculate moles of Ca^2+

Moles of Ca^2+ = Molarity Ca^2+ * volume

Moles of Ca^2+ = 0.10 * 0.500 L

Moles Ca^2+ = 0.05 moles

<u>Step 3: </u>Calculate moles of SO4^2-

Moles of SO4^2- = 0.10 * 0.500 L

Moles SO4^2- = 0.05 moles

<u>Step 4: </u>Calculate total volume

500.0 mL + 500.0 mL = 1000 mL = 1L

<u>Step 5: </u> Calculate Q

Q = [Ca2+] [SO42-]  

[Ca2+]= 0.050 M   [O42-]

Qsp = (0.050)(0.050 )=0.0025 >> Ksp

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<u> Step 6:</u> Calculate molar solubility

Ksp = 2.40 * 10^-5 = [Ca2+][SO42-] =(x)(x)

2.40 * 10^-5 = x²

x = √(2.40 * 10^-5)

x = 0.0049 M = Molar solubility

<u> Step 7:</u> Calculate total CaSO4 dissolved

total CaSO4 dissolved = 0.0049 M * 1 L * 136.14 mol/L = 0.667 g

<u>Step 8:</u> Calculate initial mass of CaSO4

Since initial moles CaSo4 = 0.050

Initial mass of CaSO4 = 0.050 * 136.14 g/mol

Initial mass of CaSO4 = 6.807 grams

<u>Step 9:</u> Calculate mass precipitate

6.807 - 0.667 = 6.14 grams

The mass of calcium sulfate that will precipitate is 6.14 grams

5 0
2 years ago
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