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Sedaia [141]
2 years ago
15

Burnem Inc. manufactures thumb drives and sells them to a distributor. Burnem's total cost and total revenue (in dollars) for x

thumb drives are given by the following equations. Total cost = 4x + 4884 and Total revenue = 15x How many thumb drives must Burnem sell to break even?
Mathematics
1 answer:
AlladinOne [14]2 years ago
3 0

Answer:

444 thumb drives

Step-by-step explanation:

Break even is the point at which the proceeds are equal to the costs i.e. when Total cost = Total revenue. So using the equations provided, the breakeven point for Burnem Inc. will be 4x + 4884 = 15x, where x is number of thumb drives. We solve for x to get the answer:

4x + 4884 = 15x

4884 = 15x - 4x

4884 = 11x

x = 4884/11

x = 444 thumb drives

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There are 345 students at a college who have taken a course in calculus, 212 who have taken a course in discrete mathematics, an
ollegr [7]

Answer:

369 students have taken a course in either calculus or discrete mathematics

Step-by-step explanation:

I am going to build the Venn's diagram of these values.

I am going to say that:

A is the number of students who have taken a course in calculus.

B is the number of students who have taken a course in discrete mathematics.

We have that:

A = a + (A \cap B)

In which a is the number of students who have taken a course in calculus but not in discrete mathematics and A \cap B is the number of students who have taken a course in both calculus and discrete mathematics.

By the same logic, we have that:

B = b + (A \cap B)

188 who have taken courses in both calculus and discrete mathematics.

This means that A \cap B = 188

212 who have taken a course in discrete mathematics

This means that B = 212

345 students at a college who have taken a course in calculus

This means that A = 345

How many students have taken a course in either calculus or discrete mathematics

(A \cup B) = A + B - (A \cap B) = 345 + 212 - 188 = 369

369 students have taken a course in either calculus or discrete mathematics

4 0
2 years ago
At most, Alana can spend $40 on carnival tickets. Ride tickets cost $4 each, and food tickets cost $2 each. Alana buys at least
evablogger [386]
We can let r be the number of food tickets and f be the number of food tickets. Since Alana can spend at most $40, that means the total of price bought for r and f must be less than or equal to $40. In addition, since Alana buys at least 16 tickets, this also means that the total of r and f is 16. Mathematically, we have these inequalities: (1) 4r + 2f ≤ 40 and (2) r + f ≥ 16 Multiplying -2 in (2), we have 4r + 2f ≤ 40 -2r - 2f ≤ 32 Adding both inequalities, 2r ≤ 8 r ≤ 4 Since r must be less than or equal to 4.Thus the answer is <span>A.</span>
5 0
2 years ago
Read 2 more answers
two companies rent moving trucks. pack and go charges $39.95 flat fee and $0.45 for every mile driven. U-drive charges $59.95 fl
Nutka1998 [239]

Answer:

$62.60

Step-by-step explanation:

C(190) = 22 + 0.1*190 = 22 + 19 = $41

C(406) = 22 + 0.1*406 = 22+40.6 = $62.60

8 0
2 years ago
Read 2 more answers
Find each product.<br> 1) (5n - 5)(4n - 4)
Paraphin [41]

Answer:

20n² - 40n + 20

Step-by-step explanation:

(5n - 5)(4n - 4)

= 5n(4n) + 5n(-4) - 5(4n) - 5(-4)

= 20n² - 20n - 20n + 20

= 20n² - 40n + 20

Another way to do this:

(5n - 5)(4n - 4)

= 5(n - 1) * 4(n - 1)

= 20(n - 1)(n - 1)

= 20(n - 1)²

= 20(n² - 2n + 1)

= 20n² - 40n + 20

6 0
2 years ago
In a camp there is food for 400 persons for 23 days-if 60 more persons join the camp find the number of days the provision will
Deffense [45]

The answer is 20 days.

After 60 people have joined there will be 460 people in the camp.

The number of days which the provisions will last will be proportional less after the 60 people have joined and will be:-

(400/460) * 23

= (20 / 23) * 23

=  20


3 0
2 years ago
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