A cat chases a mouse. The cat is originally 4 feet behind the mouse, which is running in the same direction along the same route
1 answer:
The cat will take 0.8 seconds to catch up with the mouse
Step-by-step explanation:
Given:
The distance between the cat and the mouse = 4 feet
cat's speed = 17 feet per second.
mouse's speed = 12 feet per second
To Find:
how long will it take the cat to catch up with the mouse = ?
Solution:
We know that
distance = speed x time
Rewriting the equation for time we get
time =
now we know that distance is 4 feet
and the speed is 17 -12 = 5 feet per second
Thus the time is
=
= 0.8 seconds
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<span>In triangle WXZ,
Line WY is an altitude (as shown in the attached picture)
Now, it is given that:
</span><span>If ΔYWZ ~ ΔYXW
</span>∠WXY = ∠WZY
<span>
Then, we can also conclude
</span>∠WYX = ∠WYZ = 90°....(1) (because WY is the altitude)
Now, in any triangle, the sum of all the three angles is 180.
In triangle, WXY, ∠WYX = 90° (From 1)
Therefore, WXY + XWY = 90°
Similarly, in WZY.
Hence, we conclude that XWZ is a right angle.
Line WY is an altitude (as shown in the attached picture)
Now, it is given that:
</span><span>If ΔYWZ ~ ΔYXW
</span>∠WXY = ∠WZY
<span>
Then, we can also conclude
</span>∠WYX = ∠WYZ = 90°....(1) (because WY is the altitude)
Now, in any triangle, the sum of all the three angles is 180.
In triangle, WXY, ∠WYX = 90° (From 1)
Therefore, WXY + XWY = 90°
Similarly, in WZY.
Hence, we conclude that XWZ is a right angle.
A graphing calculator shows the rocks are at the same height 1.5 seconds after they are released.
That height is 3.975 meters.
_____
f(x) = g(x)
-4.9x^2 +15 = -4.9x^2 +10x
15 = 10x . . . . . . . . . . . . . . . . . . add 4.9x^2
1.5 = x . . . . . . . . . . . . . . . . . . . divide by 10
f(1.5) = -4.9*2.25 +15 = 3.975
That height is 3.975 meters.
_____
f(x) = g(x)
-4.9x^2 +15 = -4.9x^2 +10x
15 = 10x . . . . . . . . . . . . . . . . . . add 4.9x^2
1.5 = x . . . . . . . . . . . . . . . . . . . divide by 10
f(1.5) = -4.9*2.25 +15 = 3.975