If im understanding this correctly, to find the value of the car after x amount of years, the answer would be 17,500 - 750(x)
Answer:
The amount of heat required to raise the temperature of liquid water is 9605 kilo joule .
Step-by-step explanation:
Given as :
The mass of liquid water = 50 g
The initial temperature =
= 15°c
The final temperature =
= 100°c
The latent heat of vaporization of water = 2260.0 J/g
Let The amount of heat required to raise temperature = Q Joule
Now, From method
Heat = mass × latent heat × change in temperature
Or, Q = m × s × ΔT
or, Q = m × s × (
-
)
So, Q = 50 g × 2260.0 J/g × ( 100°c - 15°c )
Or, Q = 50 g × 2260.0 J/g × 85°c
∴ Q = 9,605,000 joule
Or, Q = 9,605 × 10³ joule
Or, Q = 9605 kilo joule
Hence The amount of heat required to raise the temperature of liquid water is 9605 kilo joule . Answer
All of these would be translated versions of f(x).
A translated version is simply one in which the base equation is used and then moved. Each of these equations are quadratics with a starting term of x^2. All of them move up and down or side to side in some way and direction, but all of them would be translated versions of that graph.
After 20 minutes Clint is on page = 151
After 45 minutes Clint is on page = 181
Time slot =
minutes
Difference in pages in 25 minutes =
pages.
Lets suppose Clint is reading each page at same pace.
So , In 25 minutes, he can read = 30 pages
In 1 minute he can read =
pages
Initial time is 20 minutes, so he can read the number of pages in 20 minutes = 
So, number of pages Clint read prior to study hall were =
pages.
Alison is 2/3 of the way to the museum, so the answer is about 2/3 of 9, or 6 miles. Let's calculate it:
2 17 miles
---- * (8 1/2 miles) = -------------- She has ridden (17/3) miles, which is 5 2/3
3 3 miles.