How did knowing the number of valence electrons in one of the alien elements help to identify it? Explain how the table was used
2 answers:
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Answer :
(1) The theoretical yield of product, is, 1.257 grams.
(2) The percent yield of is, 64.13 %
(3) If the percent yield is calculated to be over 100% then there might be some impurity present in the desired product.
Solution : Given,
Mass of Mg = 0.7542 g
Molar mass of Mg = 24 g/mole
Molar mass of MgO = 40 g/mole
First we have to calculate the moles of Mg.
Now we have to calculate the moles of
The balanced chemical reaction is,
From the reaction, we conclude that
As, 2 mole of react to give 2 mole of
So, 0.03142 moles of react to give 0.03142 moles of
Now we have to calculate the mass of
Theoretical yield of = 1.257 g
Experimental yield of = 0.8922 g
Now we have to calculate the percent yield of
Therefore, the percent yield of is, 70.97 %
If the percent yield is calculated to be over 100% then the product would be greater than 1.257 g which indicates that there might be some impurity present in the desired product.
The question is missing. Here is the complete question.
Which balanced redox reaction is ocurring in the voltaic cell represented by the notation of ?
(a)
(b)
(c)
(d)
Answer: (d)
Explanation: <u>Redox</u> <u>Reaction</u> is an oxidation-reduction reaction that happens in the reagents. In this type of reaction, reagent changes its oxidation state: when it loses an electron, oxidation state increases, so it is oxidized; when receives an electron, oxidation state decreases, then it is reduced.
Redox reactions can be represented in shorthand form called <u>cell</u> <u>notation,</u> formed by: <em><u>left side</u></em> of the salt bridge (||), which is always the <em><u>anode</u></em>, i.e., its half-equation is as an <em><u>oxidation</u></em> and <em><u>right side</u></em>, which is always <em><u>the cathode</u></em>, i.e., its half-equation is always a <em><u>reduction</u></em>.
For the cell notation:
Aluminum's half-equation is oxidation:
For Lead, half-equation is reduction:
Multiply first half-equation for 2 and second half-equation by 3:
Adding them:
The balanced redox reaction with cell notation is