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Anna11 [10]
2 years ago
15

How did knowing the number of valence electrons in one of the alien elements help to identify it? Explain how the table was used

to accomplish this task.
Chemistry
2 answers:
lawyer [7]2 years ago
7 0
Knowing the number of valence electrons in one of the alien elements helps in identifying it because the number of valence electrons can help categorize the alien element. Similar elements have the same valence electrons and knowing the category of the element can help further analyze the element.
Anton [14]2 years ago
7 0

Answer:

All elements in the same group of the periodic table have the same number of valence electrons. The number of valence electrons always matches the ones place digit of the group number. Knowing the valence electrons of an alien element allows matching it with its group

Explanation:

your welcome

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B

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A 20.6-L sample of "pure" air is collected in Greenland at a temperature of 220.0°C and a pressure of 1.01 atm and is forced int
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Answer :

(a) The pressure inside the bottle just after it filled is 19.8 atm.

(b) The pressure inside the bottle as it opened in the 21.0°C is 11.8 atm.

Explanation :

<u>Part (a) :</u>

Boyle's Law : It is defined as the pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.

P\propto \frac{1}{V}

or,

P_1V_1=P_2V_2

where,

P_1 = initial pressure of gas = 1.01 atm

P_2 = final pressure of gas = ?

V_1 = initial volume of gas = 20.6 L

V_2 = final volume of gas = 1.05 L

Now put all the given values in the above equation, we get:

1.01atm\times 20.6L=P_2\times 1.05L

P_2=19.8atm

Therefore, the pressure inside the bottle just after it filled is 19.8 atm.

<u>Part (b) :</u>

Gay-Lussac's Law : It is defined as the pressure of the gas is directly proportional to the temperature of the gas at constant volume and number of moles.

P\propto T

or,

\frac{P_1}{T_1}=\frac{P_2}{T_2}

where,

P_1 = initial pressure of gas = 19.8 atm

P_2 = final pressure of gas = ?

T_1 = initial temperature of gas = 220.0^oC=273+220.0=493.0K

T_2 = final temperature of gas = 21.0^oC=273+21.0=294.0K

Now put all the given values in the above equation, we get:

\frac{19.8atm}{493.0K}=\frac{P_2}{294.0K}

P_2=11.8atm

Therefore, the pressure inside the bottle as it opened in the 21.0°C is 11.8 atm.

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