120,395 as a prrcent

The Frostburg-Truth bus travels on a straight road from Frostburg Mall to Sojourner Truth Park. The mall is 3 miles west and 4 m

geniusboy [140]

We take the distance from points which indicates the location of the park and the mall.

For distance through north and east, we have positive values and negative for west and south.

Mall: (-3, -4)
Park: (3, 5)

The distance is calculate through the equation,
d = sqrt ((x₂ - x₁)² + (y₂ - y₁)²)

Substituting,
d = sqrt ((-4 - 5)² + (-3 - 3)²
d = sqrt 117 = 10.82
Thus, the distance between the mall and the park is approximately 10.82 miles.

5 0

2 years ago

The vertex of this parabola is at (-2, -3). When the y-value is -2, the x-value is -5. Determine the coefficient of the squared

morpeh [17]

So the problem ask to calculate the coefficient of the squared term in the parabola equation and the best answer, based on my calculation and further formulation, is that the vertex of the parabola is y =a(x-h)^2+k and to simplify it i came up with an answer of x^2.

6 0

2 years ago

A car dealer recommends that transmissions be serviced at 30,000 miles. To see whether her customers are adhering to this recomm

salantis [7]

Answer:

No, the owners are not having their transmissions serviced at 30,000 miles.

Step-by-step explanation:

We are given that a car dealer recommends that transmissions be serviced at 30,000 miles.

The car dealer selects a random sample of 40 customers and finds that the average mileage of the automobiles serviced is 30,456. The standard deviation of the population is 1684 miles.

Let $\mu$ = true average mileage of the automobiles serviced.

So, Null Hypothesis, $H_0$ : $\mu$ = 30,000 miles {means that the owners are having their transmissions serviced at 30,000 miles}

Alternate Hypothesis, $H_A$ : $\mu\neq$ 30,000 miles {means that the owners are having their transmissions serviced at different than 30,000 miles}

The test statistics that will be used here is One-sample z-test statistics because we know about population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample average mileage serviced = 30,456 miles

$\sigma$ = population standard deviation = 1684 miles

n = sample of customers = 40

So, the test statistics = $\frac{30,456-30,000}{\frac{1684}{\sqrt{40} } }$

= 1.71

The value of z-statistics is 1.71.

Also, the P-value of the test statistics is given by;

P-value = P(Z > 1.71) = 1 - P(Z $\leq$ 1.71)

= 1 - 0.9564 = 0.0436

For the two-tailed test, the P-value is calculated as = 2 $\times$ 0.0436 = 0.0872.

Since the P-value of our test statistics is less than the level of significance as 0.0872 < 0.10, so we have sufficient evidence to reject our null hypothesis as the test statistics will fall in the rejection region.

Therefore, we conclude that the owners are having their transmissions serviced at different than 30,000 miles.

4 0

2 years ago

Determine the value of (tangent of 88 degrees, 22 minutes, and 45 seconds). In this case, minutes are 1/60 of a degree and secon

mariarad [96]

Answer:

c. 35.34015106

Step-by-step explanation:

As with many problems of this nature, you only need to get close to be able to choose the correct answer. 22 minutes 45 seconds is just slightly less than 1/2 degree (30 minutes), so the tangent value will be just slightly less than tan(88.5°) ≈ 38. The appropriate choice is 35.34015106.

If you need confirmation, you can find tan(88°) ≈ 29, so you know the answer will be between 29 and 38.

__

The above has to do with strategies for choosing answers on multiple-choice problems. Below, we will work the problem.

The angle is (in degrees) ...

88 + 22/60 +45/3600 = 88 + (22·60 +45)/3600 = 88 +1365/3600

≈ 88.3791666... (repeating) . . . . degrees

A calculator tells you the tangent of that is ...

tan(88.3791666...°) ≈ 35.3401510614

Many calculators will round that to 10 digits, as in the answer above. Others can give a value correct to 32 digits. Spreadsheet values will often be correct to 15 or 16 digits.

4 0

2 years ago

Ivy Tech tuition was $3090 in 2010 and $3196 in 2015. Calculate the slope, then create a linear model that would predict tuition

PSYCHO15rus [73]

Answer:

Part a) The slope is equal to $m=21.2\frac{\$}{year}$