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igomit [66]
2 years ago
7

Electrolysis of molten MgCl2 is the final production step in the isolation of magnesium from seawater by the Dow process. Assumi

ng that 38.0 g of Mg metal forms, answer the following questions. (a) How many moles of electrons are required? 2 mol e− (b) How many coulombs are required? 1.93 × 10 5 C Enter your answer in scientific notation. (c) How many amps will produce this amount in 3.50 h? A
Chemistry
1 answer:
fomenos2 years ago
7 0

Answer:

24.25A

Explanation:

Mg(aq) + 2e --------> Mg(s)

Two moles of electrons are required

1 mole of electron requires 1F of electricity

1F= 96500C

Since 2 moles of electrons are involved, 2F are involved that means 2×96500= 1.93×10^5C.

Mass of Mg produced from reduction equation=24g

But q=It and t must be in seconds.

If 1.93×10^5C produces 24g of Mg

3.5×60×60×I will produce 38.0g of Mg

Therefore I= 24.25A

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Stu Dent has finished his titration, and he comes to you for help with the calculations. He tells you that 20.00 mL of unknown c
Alexus [3.1K]

Answer:

0.3229 M HBr(aq)

0.08436M H₂SO₄(aq)

Explanation:

<em>Stu Dent has finished his titration, and he comes to you for help with the calculations. He tells you that 20.00 mL of unknown concentration HBr(aq) required 18.45 mL of 0.3500 M NaOH(aq) to neutralize it, to the point where thymol blue indicator changed from pale yellow to very pale blue. Calculate the concentration (molarity) of Stu's HBr(aq) sample.</em>

<em />

Let's consider the balanced equation for the reaction between HBr(aq) and NaOH(aq).

NaOH(aq) + HBr(aq) ⇄ NaBr(aq) + H₂O(l)

When the neutralization is complete, all the HBr present reacts with NaOH in a 1:1 molar ratio.

18.45 \times 10^{-3} L NaOH.\frac{0.3500molNaOH}{1LNaOH} .\frac{1molHBr}{1molNaOH} .\frac{1}{20.00 \times 10^{-3} LHBr} =\frac{0.3229molHBr}{1LHBr} =0.3229M

<em>Kemmi Major also does a titration. She measures 25.00 mL of unknown concentration H₂SO₄(aq) and titrates it with 0.1000 M NaOH(aq). When she has added 42.18 mL of the base, her phenolphthalein indicator turns light pink. What is the concentration (molarity) of Kemmi's H₂SO₄(aq) sample?</em>

<em />

Let's consider the balanced equation for the reaction between H₂SO₄(aq) and NaOH(aq).

2 NaOH(aq) + H₂SO₄(aq) ⇄ Na₂SO₄(aq) + 2 H₂O(l)

When the neutralization is complete, all the H₂SO₄ present reacts with NaOH in a 1:2 molar ratio.

42.18 \times 10^{-3} LNaOH.\frac{0.1000molNaOH}{1LNaOH} .\frac{1molH_{2}SO_{4}}{2molNaOH} .\frac{1}{25.00\times 10^{-3}LH_{2}SO_{4}} =\frac{0.08436molH_{2}SO_{4}}{1LH_{2}SO_{4}} =0.08436M

6 0
2 years ago
Calculate the molar mass of a gas that diffuses three times faster than oxygen under similar conditions.
JulsSmile [24]
<span> rate 3/1= square root of 32/x
square both sides
9/1=32x
x = 32/9
= 3.6
Must be He
molar mass =4
</span>
7 0
2 years ago
Read 2 more answers
Rank the formation of the solutions A, B, and C from the most exothermic to the most endothermic. Rank the enthalpy of solution
Elodia [21]

This is an incomplete question, the table is attached below.

Answer : The correct ranking of the solution from most exothermic to most endothermic will be: A, B and C.

Explanation :

As we know that the intermolecular force of attraction play an important role in the interaction of solute-solute, solute-solvent and solvent solvent solution.

In the solution A, the solute-solute and solvent-solvent interactions are weak. So, their solute-solvent interaction will be strong. That means, the solution will be more exothermic.

In the solution C, the solute-solute and solvent-solvent interactions are strong. So, their solute-solvent interaction will be weak. That means, the solution will be more endothermic.

Thus, the correct ranking of the solution from most exothermic to most endothermic will be: A, B and C.

4 0
2 years ago
URGENT!! 50 Points Please Help!! Will mark brainliest!! Assignment due in 30 minutes.
dedylja [7]

a) The least number of decimal points is 0 so you should round the answer to 43.

b) The least number of significant figures is 2 so round to 7.3

c)The least number of decimal places is 1 so round to 225.7

d) The least number of significant figures is 3 so round to 92.0

e) The least number of significant figures is 3 so round to 32.4

f) The least number of decimal places is 0 so round to 104m^3

Basically, for addition and subtraction round to the least number of decimal places found in the factors, and for multiplication and division round to the least number of significant figures found in the factors.

4 0
2 years ago
the hydrogen gas generated when calcium metal reacts with water is collected over water at 20 degrees C. The volume of the gas i
Gala2k [10]

Answer:

There is 0.0677 grams of H2 gas obtained

Explanation:

Step 1: Data given

The total pressure (988 mmHg) is the sum of the pressure of the collected hydrogen + the vapor pressure of water (17.54 mmHg).  

ptotal = p(H2)+ p(H2O)

p(H2) = ptotal - pH2O = 988 mmHg - 17.54 mmHg = 970.46 mmHg

Step 2: Calculate moles of H2 gas

Use the ideal gas law to calculate the moles of H2 gas

PV = nRT

n = PV / RT

 ⇒ with p = pressure of H2 in atm = 970.46 mmHg * (1 atm /760 mmHg) = 1.277 atm

⇒ V = volume of H2 in L = 641 mL x (1 L / 1000 mL) = 0.641 L

⇒ n = the number of moles of H2 = TO BE DETERMINED

⇒ R = the gas constant = 0.08206 L*atm/K*mol

⇒ T = the temperature = 20.0 °C = 293.15 Kelvin

n = (1.277)(0.641) / (0.08206)(298.15) = 0.0335 moles H2

Step 3: Calculate mass of H2

Mass of H2 = moles H2 ¨molar H2

0.0335 moles H2 * 2.02 g/mol H2  = 0.0677g H2

There is 0.0677 grams of H2 gas obtained

7 0
2 years ago
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