3 1/2 hours because Rodriquez graded one hour of papers and if his assistant grades the class papers in 4 1/2 hours, it should only take him 3 1/2 hours since Rodriquez helped with an hour of it
Answer:
½log3 + ½logx
Step-by-step explanation:
½(log(3x))
½(log3 + logx)
½logx + ½log3
The houses can be placed in 362,880 ways.
<u>Step-by-step explanation:</u>
The 9 houses are each in different design.
The each lot can place any of the 9 houses.
- The 1st lot can place anyone house of all the 9 houses.
- The 2nd lot can place one of remaining 8 houses.
- The 3rd lot can place one of remaining 7 houses.
Similarly, the process gets repeated until the last house is placed on a lot.
<u>From the above steps, it can be determined that :</u>
The number of ways to place the 9 houses in 9 lots = 9!
⇒ 9×8×7×6×5×4×3×2×1
⇒ 362880 ways.
Therefore, the houses can be placed in 362880 ways.
The complete problem wants to know the more cost-effective choice is the printing company replaces its press machine every four years.
With this in mind, if they choose Company A, the total amount that needs to be paid to cover 12(4) = 48 months will be
Company A = 9 500 + 48(750) = $13 100
As for Company B, the highest probability of not having any repairs over the four years is 0.32 while there's 0.14 chance that number of repairs will be 3 over the time the contract is applied.
This means that the possible amounts to be paid to Company B are
Company B = 10 500 + 0(150) = $10 500
Company B = 10 500 + 1(150) = $10 650
Company B = 10 500 + 2(150) = $10 800
Company B = 10 500 + 3(150) = $10 950
This shows that choosing the machine from Company B would be better.
Hence, the answer is Company B<span>.</span>
So the questions ask to write an equations that shows how much money will be donated and then solve. So let Y be the amount of money and X will be the number of people attending. So the equation would be y=(10-5.5)X so the answer would be Y=2250. I hope you are satisfied with my answer and feel free to ask for more
