answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
loris [4]
2 years ago
3

A fatigue test was conducted in which the mean stress was 50 MPa (7250 psi) and the stress amplitude was 225 MPa (32,625 psi). (

a) Compute the maximum and minimum stress levels.
Engineering
2 answers:
Damm [24]2 years ago
7 0
<h2>Complete Question:</h2><h2 />

A fatigue test was conducted in which the mean stress was 50 MPa (7,250 psi) and the stress amplitude was 225 MPa (32,625 psi).

(a) Compute the maximum and minimum stress levels.

(b) Compute the stress ratio.

(c) Compute the magnitude of the stress range.

<h2></h2><h2>Answer:</h2><h2></h2>

(a) The maximum and minimum stress levels are 275MPa and -175MPa respectively.

(b) The stress ratio is 0.6

(c) The magnitude of the stress range is 450MPa

<h2>Explanation:</h2><h2></h2>

(a )In fatigue, the mean stress (S_{m}) is found by finding half of the sum of the maximum stress (S_{max}) and minimum stress (S_{min}) levels. i.e

S_{m} = \frac{S_{max} + S_{min}}{2}    ------------------------(i)

Also, the stress amplitude (also called the alternating stress), S_{a}, is found by finding half of the difference between the maximum stress (S_{max}) and minimum stress (S_{min}) levels. i.e

S_{a} = \frac{S_{max} - S_{min}}{2}    ------------------------(ii)

<em>From the question, </em>

S_{m} = 50 MPa (7250 psi)

S_{a} = 225 MPa (32,625 psi)

<em>Substitute these values into equations(i) and (ii) as follows;</em>

50 = \frac{S_{max} + S_{min}}{2}

=> 100 = S_{max} + S_{min}          -------------------(iii)

225 = \frac{S_{max} - S_{min}}{2}

=> 450 = S_{max} - S_{min}          -------------------(iv)

Now, solve equations (iii) and (iv) simultaneously as follows;

<em>(1) add the two equations;</em>

     100 = S_{max} + S_{min}

     450 = S_{max} - S_{min}

    ________________

     550 = 2S_{max}               --------------------------------(v)

    _________________

<em>(2) Divide both sides of equation (v) by 2 as follows;</em>

     \frac{550}{2} = \frac{2S_{max} }{2}

     275 = S_{max}

Therefore, the maximum stress level is 275MPa

<em>(3) Substitute </em>S_{max} = 275 into equation (iv) as follows;

   450 = 275 - S_{min}

   S_{min} = 275 - 450

  S_{min} = -175

Therefore, the minimum stress level is -175MPa

In conclusion, the maximum and minimum stress levels are 275MPa and -175MPa respectively.

===============================================================

(b) The stress ratio (S_{r}) is given by;

S_{r} = \frac{S_{min} }{S_{max} }        ----------------------------(vi)

<em>Insert the values of </em>S_{max}<em> and </em>S_{min}<em> into equation (vi)</em>

S_{r} = \frac{-175}{275}

S_{r} = 0.6

Therefore, the stress ratio is 0.6

===============================================================

(c) The magnitude of the stress range (S_{R}) is given by

S_{R} = | S_{max} - S_{min} |          ------------------------------(vii)

<em>Insert the values of </em>S_{max}<em> and </em>S_{min}<em> into equation (vii)</em>

S_{R} = | 275 - (-175) |

S_{R} =  450MPa

Therefore, the magnitude of the stress range is 450MPa

===============================================================

<h2>Note: </h2>

1 MPa = 145.038psi

Therefore, the values of the maximum and minimum stress levels, the stress range can all be converted from MPa to psi (pounds per inch square) by multiplying the values by 145.038 as follows;

S_{max} = 275MPa = 275 x 145.038psi = 39885.45psi

S_{min} = -175MPa = -175 x 145.038psi = 25381.65psi

S_{R} =  450MPa = 450 x 145.038psi = 65267.1psi

Sloan [31]2 years ago
5 0

Answer:

\sigma_{max} = 275\,MPa, \sigma_{min} = - 175\,MPa

Explanation:

Maximum stress:

\sigma_{max}=\overline \sigma + \sigma_{a}\\\sigma_{max}= 50\,MPa + 225\,MPa\\\sigma_{max} = 275\,MPa

Minimum stress:

\sigma_{min}=\overline \sigma - \sigma_{a}\\\sigma_{min}= 50\,MPa - 225\,MPa\\\sigma_{min} = - 175\,MPa

You might be interested in
Consider film condensation on a vertical plate. Will the heat flux be higher at the top or at the bottom of the plate? Why?
STALIN [3.7K]

Answer:

During film condensation on a vertical plate, heat flux at the top will be higher since the thickness of the film at the top, and thus its thermal resistance, is lower.

Explanation:

https://www.docsity.com/pt/cengel-solution-heat-and-mass-transfer-2th-ed-heat-chap10-034/4868218/

https://arc.aiaa.org/doi/pdf/10.2514/1.43136

https://arxiv.org/ftp/arxiv/papers/1402/1402.5018.pdf

8 0
2 years ago
A thermal energy storage unit consists of a large rectangular channel, which is well insulated on its outer surface and encloses
yaroslaw [1]

Answer:

the temperature of the aluminum at this time is 456.25° C

Explanation:

Given that:

width w of the aluminium slab = 0.05 m

the initial temperature T_1 = 25° C

T{\infty} =600^0C

h = 100 W/m²

The properties of Aluminium at temperature of 600° C by considering the conditions for which the storage unit is charged; we have ;

density ρ = 2702 kg/m³

thermal conductivity k = 231 W/m.K

Specific heat c = 1033 J/Kg.K

Let's first find the Biot Number Bi which can be expressed by the equation:

Bi = \dfrac{hL_c}{k} \\ \\ Bi = \dfrac{h \dfrac{w}{2}}{k}

Bi = \dfrac{hL_c}{k} \\ \\ Bi = \dfrac{100 \times \dfrac{0.05}{2}}{231}

Bi = \dfrac{2.5}{231}

Bi = 0.0108

The time constant value \tau_t is :

\tau_t = \dfrac{pL_cc}{h} \\ \\ \tau_t = \dfrac{p \dfrac{w}{2}c}{h}

\tau_t = \dfrac{2702* \dfrac{0.05}{2}*1033}{100}

\tau_t = \dfrac{2702* 0.025*1033}{100}

\tau_t = 697.79

Considering Lumped capacitance analysis since value for Bi is less than 1

Then;

Q= (pVc)\theta_1 [1-e^{\dfrac {-t}{ \tau_1}}]

where;

Q = -\Delta E _{st} which correlates with the change in the internal energy of the solid.

So;

Q= (pVc)\theta_1 [1-e^{\dfrac {-t}{ \tau_1}}]= -\Delta E _{st}

The maximum value for the change in the internal energy of the solid  is :

(pVc)\theta_1 = -\Delta E _{st}max

By equating the two previous equation together ; we have:

\dfrac{-\Delta E _{st}}{\Delta E _{st}{max}}= \dfrac{  (pVc)\theta_1 [1-e^{\dfrac {-t}{ \tau_1}}]} { (pVc)\theta_1}

Similarly; we need to understand that the ratio of the energy storage to the maximum possible energy storage = 0.75

Thus;

0.75=  [1-e^{\dfrac {-t}{ \tau_1}}]}

So;

0.75=  [1-e^{\dfrac {-t}{ 697.79}}]}

1-0.75=  [e^{\dfrac {-t}{ 697.79}}]}

0.25 =  e^{\dfrac {-t}{ 697.79}}

In(0.25) =  {\dfrac {-t}{ 697.79}}

-1.386294361= \dfrac{-t}{697.79}

t = 1.386294361 × 697.79

t = 967.34 s

Finally; the temperature of Aluminium is determined as follows;

\dfrac{T - T _{\infty}}{T_1-T_{\infty}}= e ^ {\dfrac{-t}{\tau_t}}

\dfrac{T - 600}{25-600}= e ^ {\dfrac{-967.34}{697.79}

\dfrac{T - 600}{25-600}= 0.25

\dfrac{T - 600}{-575}= 0.25

T - 600 = -575 × 0.25

T - 600 = -143.75

T = -143.75 + 600

T = 456.25° C

Hence; the temperature of the aluminum at this time is 456.25° C

3 0
2 years ago
6. You are an electrician working in an industrial plant. You are building a motor control cabinet that contains six motor start
Sveta_85 [38]

Answer:

It's indeed safer to suggest a 150 VA transformer. Following table however is the clarification given.

Explanation:

For 2 motors with 0.1 A, the Power will be:

P = 2\times 120\times 0.1

  = 24 \ W

For 4 motors with 0.18 A, the Power will be:

P = 4\times 120\times 0.18

  = 86.4 \ W

As we know, for 6 pilot lamps, the power is "5 W".

So,

The total power will be:

⇒ P = 24+86.4+5

       = 115.4 \ W

Now,

Consider the power factor to be "0.95"

VA of transformer is:

= PF\times Power

= 115.4\times 0.9

= 109.63 \ VA

8 0
2 years ago
Your task is to fill in the missing parts of the C code to get a program equivalent to the generated assembly code. Recall that
Rudik [331]

Answer:

See Explaination

Explanation:

//Function

long loop (long x, long n)

{

//Declare a variable named result and initialize it to zero

long result = 0;

//Declare a variable named mask

long mask;

//For loop

for(mask = 1; mask != 0; mask = mask << (n & 0xFF))

{

//Calculate

result | = (x&mask);

}

//Return result

return result;

}

6 0
2 years ago
During an experiment conducted in a room at 25°C, a laboratory assistant measures that a refrigerator that draws 2 kW of power h
zvonat [6]

Answer:

Not reasonable.

Explanation:

To solve this problem it is necessary to take into account the concepts related to the performance of a reversible refrigerator. The coefficient of performance is basically defined as the ratio between the heating or cooling provided and the electricity consumed. The higher coefficients are equivalent to lower operating costs. The coefficient can be greater than 1, because it is a percentage of the output: losses, other than the thermal efficiency ratio: input energy. For a reversible refrigerator the coefficient is given by

COP_{R,rev} = \frac{1}{\frac{T_1}{T_2}-1}

Where,

T_1 =High temperature

T_2 =Low Temperature

With our values previous given we can find it:

T_2 = -30\°C = (-30+273)

T_2 = 243K

T_1 = 25\°C = (25+273)

T_1 = 298K

With these values we can now calculate the coefficient of performance:

COP_{R,rev} = \frac{1}{\frac{298}{243}-1}

COP_{R,rev} = 4.42

At the same time we can calculate the work consumption of the refrigerator, this is

W = \dot{W}\Delta t

Where,

\dot{W} = Required power input

t = time to remove heat from a cool to water medium

W = 2kJ/s * 20 min

W = 2kJ/s * 1200s

W = 2400kJ

In this way we can calculate the coefficient of the refrigerator directly:

COP_R = \frac{Q_L}{W}

Where,

Q = Amoun of heat rejected

COP_R = \frac{30000}{2400}

COP_R = 12.5

Comparing the values of both coefficients we have that the experiments are NOT reasonable, because the coefficient of a refrigerator is high compared to  coefficient of reversible refrigerator.

5 0
2 years ago
Other questions:
  • A 60-kg woman holds a 9-kg package as she stands within an elevator which briefly accelerates upward at a rate of g/4. Determine
    14·1 answer
  • Determine the amount of gamma and alpha phases in a 10-kg, 1060 steel casting as it is being cooled to the following temperature
    6·1 answer
  • A square loop of wire surrounds a solenoid. The side of the square is 0.1 m, while the radius of the solenoid is 0.025 m. The sq
    6·1 answer
  • Some states have osha programs, but you should always defer to the federal program.
    8·2 answers
  • The function below takes a single string parameter: input_string. If the input contains the lowercase letter z, return the strin
    15·1 answer
  • Five Kilograms of continuous boron fibers are introduced in a unidirectional orientation into of an 8kg aluminum matrix. Calcula
    9·1 answer
  • A sample of normally consolidated clay was subjected to a CU triaxial compression test that was carried out until the specimen f
    6·1 answer
  • Anytime scaffolds are assembled or __________, a competent person must oversee the operation.
    15·2 answers
  • Lydia is the CEO for a large pharmaceutical manufacturer. Her company is in the final stages of FDA
    12·1 answer
  • How does Accenture generate value for clients through Agile and DevOps?
    15·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!