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nlexa [21]
2 years ago
14

A load P is applied horizontally while the other end is fixed to a structure. where P = 185 N You have already examined the axia

l stresses inside the plates. In this problem, the bolted connections will be analyzed. Failure means that the pieces come apart because the bolts cannot hold the force. If two bolts are connecting the two plates, how much transverse force V must each bolt resist at each sheare joint?
Engineering
1 answer:
tigry1 [53]2 years ago
5 0

Answer:

Explanation:

The bolt is under double shear because it connects 3 plates.

Now the shear force resisted by each shear joint(V):

V=P/(No. of shear area)=185/2=92.5N.

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Explanation:

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Properties of Carpenter's hammer possess

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A cylindrical specimen of a brass alloy having a length of 60 mm (2.36 in.) must elongate only 10.8 mm (0.425 in.) when a tensil
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The radius of the specimen is 60 mm

<u>Explanation:</u>

Given-

Length, L = 60 mm

Elongated length, l = 10.8 mm

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radius, r = ?

We are supposed to calculate the radius of a cylindrical brass specimen in order to produce an elongation of 10.8 mm when a load of 50,000 N is applied. It is necessary to compute the strain corresponding to this

elongation using Equation:

ε = Δl / l₀

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σ = F / A

Where A = πr²

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