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2 years ago

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A scale drawing of a dance floor is has a length of 22 inch, a height of 14 cm, and has a scale of 5 cm: 8 ft. What is the area

of the actual dance floor? A) 600 ft B) 480.35 ft C) 800.25 ft D) 788.48 ft

1 answer:

olganol [36]2 years ago

5 0

Answer: OPTION D

Step-by-step explanation:

The missing figure is attached.

According to the data given in the exercise, the scale used is the following:

$5\ cm:\ 8 ft$

Then, if in the scale drawing the dance floor has a length of 22 centimeters, then its actual length is:

$l=\frac{22\ cm*8\ ft}{5\ cm}\\\\l=35.2\ ft$

If in the scale drawing the dance floor has a height of 14 centimeters, then its actual height is:

$h=\frac{14\ cm*8\ ft}{5\ cm}\\\\h=22.4\ ft$

Finally, in order to calculate the area of the actual dance floor, you need to multiply its dimensions.

Therefore, you get that its area is:

$A=(35.2\ ft)(22.4\ ft)\\\\A=788.48\ ft^2$

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Answer:

a) $\bar X=10.65$

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And we can find the usual limits with:

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Step-by-step explanation:

We have the following data:

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Part a

We can calculate the sample mean with the following formula:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

And if we replace we got: $\bar X=10.65$

For the median we need to sort the values on increasing order and we have:

8.3 10.3 10.5 10.6 10.7 10.7 10.9 11.2 11.5 11.8

Since n =10 we can calculate the median as the average between the 5th and 6th position of the dataset ordered and we got:

$Median =\frac{10.7+10.7}{2}=10.7$

The mode would be the most repeated value on this case:

$Mode= 10.7$

Part b

The range is defined as $Range =Max-Min$ and if we replace we got:

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We can calculate the standard deviation with the following formula:

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And if we replace we got:

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Part c

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We can calculate the first quartile with these values: 8.3 10.3 10.5 10.6 10.7 10.7 and $Q_1= \frac{10.6+10.7}{2}=10.55$

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And they should be considered apply some strategies to reduce the response time, adding more stations around points selected at the city could be useful in order to reduce the response time.

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