Question

At a bridal store, 73% of customers buy a wedding dress . Only 52% of customers get a wedding dress and get a veil. What is the probability that a customer who gets a wedding dress also gets a veil? Round your answer to the nearest tenth of a percent.

Answer 1

Answer:

71.2%

Step-by-step explanation:

The probability of events A and B happening together is

$P(A \:and\: B ) = P(A)*P(B\vert A)$

Now, the event A is costumers buying a wedding dress and its probability is

$P(A)= 73\%$.

And the probability that a costumer gets a wedding dress AND a veil is

$P(A \:and\: B ) = 52\%$

Therefore, the probability $P(B\vert A)$ that a costumer who gets a wedding dress also gets a veil is

$P(B\vert A) = \dfrac{P(A \:and\: B )}{P(A)} )$

$P(B\vert A) = \dfrac{52\% }{73\%}$

$\boxed{P(B\vert A) = 71.2\%}$