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Ulleksa [173]
2 years ago
8

What is the probability that a point chosen at random in the triangle is also in the blue square? A blue square inside of an uns

haded triangle. The triangle has a base of 9 inches and height of 6 inches. The square has side lengths of 3 inches. StartFraction 1 over 6 EndFraction One-third One-half 1
Mathematics
1 answer:
Dmitrij [34]2 years ago
5 0

Answer:

One-third

Step-by-step explanation:

we know that

The probability that a point chosen at random in the triangle is also in the blue square is equal to divide the area of the square by the area of triangle

step 1

Determine the area of triangle

A=\frac{1}{2}(9)(6)=27\ in^2

step 2

Determine the area of the square

A=(3^2)=9\ in^2

step 3

Determine the probability

P=\frac{9}{27}

simplify

P=\frac{1}{3}

therefore

One-third

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Mr. Snow bought 90 grams of Christmas candy for each of his 14 grandchildren. How many total kilograms of candy did he buy?
nignag [31]

Answer:

1.26 kg.

Step-by-step explanation:

We have been given that Mr. Snow bought 90 grams of Christmas candy for each of his 14 grandchildren. We are asked to find the amount of candy bought by Mr. Snow in kilograms.

First of all, we will find the amount of candy in grams by multiplying 90 grams by 14 as:

\text{Amount of candy bought in grams}=14\times 90

\text{Amount of candy bought in grams}=1260

We know that 1 kilogram is equal to 1000 grams. To convert 1260 grams into kg, we will divide 1260 by 1000 as:

\text{Amount of candy bought in kilograms}=\frac{1260}{1000}

\text{Amount of candy bought in kilograms}=1.26

Therefore, Mr. Snow bought 1.26 kilograms of candy.

7 0
2 years ago
Angle PSR measures 99°. Point S has three lines extending from it. One line extends to point P, another to point Q, and the othe
liberstina [14]

Answer:

45 degree

Step-by-step explanation:

We are given that

Angle PSR=99 degrees

Angle PSQ=(3x+18) degrees

Angle QSR=(9x-27)degrees

According to question

Angle PSR=Angle PSQ+angle QSR

Substitute the values

99=3x+18+9x-27

12x-9=99

12x=99+9=108

x=\frac{108}{12}=9

Substitute the value of x

Angle PSQ=(3(9)+18)=45^{\circ}

Hence, the measure of angle PSQ=45 degree

4 0
2 years ago
Read 2 more answers
A pizza lover wants to compare the average delivery times for four local pizza restaurants. Over the course of a few weeks, he o
xenn [34]

Answer:

At least two of the restaurant have different mean delivery time.

Step-by-step explanation:

The ANOVA known as Analysis of variance involves the hypothesis testing of means on the basis of variances. The null hypothesis in ANOVA is taken as the equality mean i.e. H0: All means are equal. Whereas alternative hypothesis consists of at least two means are not equal.

The problem states that a pizza lover is comparing average delivery time. The null and alternative hypothesis in this case would be

H0: All restaurant have equal mean delivery time.

H1: At least two restaurant have different mean delivery time.

8 0
2 years ago
A web server hosting company advertises 99.999 percent guaranteed network uptime. (a) how many independent network servers would
miv72 [106K]
The solution for this problem would be:
Given that there is 99.999%.

Let denote n as the network servers and p as the reliability of each server.
So the probability that the network uptime = 1 - (1 - p)^n

Therefore, (1-p) ^n = 0.00001


a. x= log(1-.99999)÷log(1-.97)= 3.2833 is the answer


1-(1-.97)^3= 0.99999 + 0.0001 = 1


b. x = log(1-.99999)÷log(1-.88) = 5.43 is the answer


1-(1-.88)^3= 0.99 + 0.0001 = approx 1
4 0
2 years ago
Sunny earns \$12$12dollar sign, 12 per hour delivering cakes. She worked for xxx hours this week. Unfortunately, she was charged
dezoksy [38]

Answer:

12x - 15 dollars

Step-by-step explanation:

Sunny earns $12 per hour for delivering cakes.

She worked for x hours this week.

Unfortunately, she was charged $15 for a late delivery on Tuesday

She was supposed to earn $12 × x = $12x this week

But she was charged $15 for late delivery on Tuesday

So her net earning this week is; $12x - $15

7 0
2 years ago
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