Write the syntax definitions of the following objects:

An annealed copper strip of 228 mm wide and 25 mm thick being rolled to a thickness of 20 mm, in one pass. The roll radius is 30

sdas [7]

Answer:

The roll force is 1.59 MN

The power required in this operation is 644.96 kW

Explanation:

Given;

width of the annealed copper, w = 228 m

thickness of the copper, h₀ = 25 mm

final thickness, hf = 20 mm

roll radius, R = 300 mm

The roll force is given by;

$F = LwY_{avg}$

where;

w is the width of the annealed copper

$Y_{avg}$ is average true stress of the strip in the roll gap

L is length of arc in contact, and for frictionless situation it is given as;

$L = \sqrt{R(h_o-h_f)} \\\\L = \sqrt{300(25-20)}\\\\L = 38.73 \ mm$

Now, determine the average true stress, $Y_{avg}$ , for the annealed copper;

The absolute value of the true strain, ε = ln(25/20)

ε = 0.223

from true stress vs true strain graph; at true strain of 0.223, the true stress is 280 MPa.

Then, the average true stress = ¹/₂(280 MPa.) = 180 MPa

Finally determine the roll force;

$F = LwY_{avg}$

$F = (\frac{38.73 }{1000})(\frac{228}{1000})*180 \ MPa\\\\F = 1.59 \ MN$

The power required in this operation is given by;

$P = \frac{2\pi FLN}{60}\\\\P = \frac{2\pi (1.59*10^6)(0.03873)(100)}{60}\\\\P = 644955.2 \ W\\\\P = 644.96 \ kW$

5 0

2 years ago

A group of statisticians at a local college has asked you to create a set of functions that compute the median and mode of a set

iVinArrow [24]

Answer:

Functions to create a median and mode of a set of numbers

Explanation:

def median(list):

if len(list) == 0:

return 0

list.sort()

midIndex = len(list) / 2

if len(list) % 2 == 1:

return list[midIndex]

else:

return (list[midIndex] + list[midIndex - 1]) / 2

def mean(list):

if len(list) == 0:

return 0

list.sort()

total = 0

for number in list:

total += number

return total / len(list)

def mode(list):

numberDictionary = {}

for digit in list:

number = numberDictionary.get(digit, None)

if number == None:

numberDictionary[digit] = 1

else:

numberDictionary[digit] = number + 1

maxValue = max(numberDictionary.values())

modeList = []

for key in numberDictionary:

if numberDictionary[key] == maxValue:

modeList.append(key)

return modeList

def main():

print "Mean of [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]: ", mean(range(1, 11))

print "Mode of [1, 1, 1, 1, 4, 4]:", mode([1, 1, 1, 1, 4, 4])

print "Median of [1, 2, 3, 4]:", median([1, 2, 3, 4])

main()

3 0

2 years ago

Read 2 more answers

Universal Containers has a junction object called "Job Production Facility". With 2 master-detail relationships to the Job and P

alexdok [17]

Answer:

C. The user will not be able to see the junction object records or the field values.

Explanation:

For the profile of the user to give access permission such as create and read to the job without granting access permission to the production facility object, the value of the field or records of the junction object will not be seen by the user. This is one of the necessary criteria or principle for the universal container with a junction object.

3 0

2 years ago

If you have power steering and you are able to __________, you should have your vehicle checked out by a qualified technician.

svp [43]

Answer: drive

Explanation:

The best word that would fit this sentence is drive. A vehicle owner should know how to drive, and they can get their vehicle checked by a qualified technician. The best word that would fit this sentence is drive. If you have power steering and you are able to <u>drive</u>, you should have your vehicle checked by a qualified technician.

8 0

2 years ago

The extruder head in a fused- deposition modeling setup has a diameter of 1.25 mm (0.05 in) and produces layers that are 0.25mm

Angelina_Jolie [31]

Answer:

The time taken will be "1 hour 51 min". The further explanation is given below.

Explanation:

The given values are:

Number of required layers:

= $\frac{38}{0.25}$