Magnus Tech owns 30% of Mirika Inc. and accounts for the investment using the equity method. During the year, Mirika reports a n
1 answer:
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Answer:
total payoff = $50000
Explanation:
solution
The payment is indicated on a specific node in a circular format.
This is the sum of the results and their possibilities.
we get here now total payoff node is
total payoff = 0.5 × $100,000 + 0.5 × 0
total payoff = $50000
and given the number, it shows that the right decision is the cancer lab. This is because it has the highest price with expected 60000
Answer:
210
Explanation:
Let us consider that x is the number of soldiers produced each week and y is number of trains produced each week.
Also, weekly revenues and costs can be expressed in terms of the decision variables x and y.
Then,
Hence the profit which we want to maximize is given by,
Now the constraints are given as,
Finishing Constraint:
Each week, no more than 100 hours of finishing time may be used.
Carpentry Constraint:
Each week, no more than 80 hours of carpentry time may be used.
Demand Constraint:
Because of limited demand, at most 40 soldiers should be produced each week.
Combining the sign restrictions and with the objective function and constraints,and yield the following optimization model:
Such that,
First convert the given inequalities into equalities:
From equation (1):
If x=0 in equation (1) then (0,100)
If y=0 in equation (1) then (50,0)
From equation (2):
If x=0 in equation (2) then (0,80)
If y=0 in equation (2) then (80,0)
From equation (3):
Equation (3) is the line passing through the point x=40.
Therefore, the given LPP has a feasible solution first image
The optimum solution for the given LPP is obtained as follows in the second image
The optimal solution to this problem is,
And the optimum values are .
Let c be the contribution to profit by each train. We need to find the values of c for which the current, basis remain optimal. Currently c is 2, and each iso-profit line has the form
3x + 2y = constant
y = 3x/2 +constant/ 2
And so, each iso-profit line has a slope of .
From the graph we can see that if a change in c causes the isoprofit lines to be flatter than the carpentry constraint, then the optimal solution will change from the current optimal solution to a new optimal solution, If the profit for each train is c, the slope of each isoprofit line will be.
-3/c
Because the slope of the carpentry constraint is –1, the isoprofit lines will be flatter than the carpentry constraint.
If,
-3/c<-1
c >3
and the current basis will no longer be optimal. The new optimal solution will be point A of the graph.
If the is oprofit lines are steeper than the finishing constraint, then the optimal solution will change from point B to point C. The slope of the finishing constraint is –2.
If,
-3/c < -2 or
C < 1.5
Then the current basis is no longer optimal and point C,(40,20), will be optimal. Hence when the contribution to the profit for trains is between $1.50 and $3, the current basis remains optimal.
Again, consider the contribution to the profit for trains is $2.50, then the decision variables remain the same since the contribution to the profit for trains is between $1.50 and $3. And the optimal solution is given by,
z = 3× (20) + 2.5 × (60)
= 60 + 150
= 210
Answer:
The correct answer for you question is $53, 300, 000
Explanation:
I have attached the complete question for you refrence.
Answer : $53,300,000
Explanation:
Equity investment in Safestyle: Amount $'m
Year 2019:
Cash 50
add: Net Income 2019. 3
less: Impairment of Goodwill 2019 -1
Closing Balance 2019. 52
Year 2020:
Opening Balance 2020 52
add: Net Income 2020 1.8
less: Impairment of Goodwill 2020 -0.5
Closing Balance 2020 53.3
