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maksim [4K]
1 year ago
11

1. An assembly line with 30 activities is to be balanced. The total amount of time to complete all 30 activities is 60 minutes.

The longest activity takes 2.4 minutes, and the shortest takes 0.3 minute. The line will operate for 480 minutes per day.
a. What are the maximum and minimum cycle times?

b. How much daily output will be achieved by each of those cycle times?

2. In problem 1, suppose the line is balanced using 14 workstations and a finished product can be produced every 4.5 minutes.

a. What is the production rate in units per day?

b. What is the assembly-line efficiency?
Business
1 answer:
trapecia [35]1 year ago
5 0

Answer:

a. What are the maximum and minimum cycle times?

The maximum cycle time is 60 minutes and the minimum cycle time is 2.4 minutes.

b. How much daily output will be achieved by each of those cycle times?

Daily output = CT = A/R

For max CT = 480/60 = 8 units per day

For min CT = 480/2.4 = 200 units per day.

2. In problem 1, suppose the line is balanced using 14 workstations and a finished product can be produced every 4.5 minutes.

a. What is the production rate in units per day?

CT = A/R or 4.5 = 480/R or R = 106.66 units/day

b. What is the assembly-line efficiency?

Efficiency = 60/[4.5(14)] =0.95 or 95.2% percent efficiency.

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Allocation of Package Purchase Price Tamarack Company purchased a plant from one of its suppliers. The $1,000,000 purchase price
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Answer:

The total purchase price of the plant allocated to the land, building, and machinery is $140,840, $509,707 and $355,453 respectively

Explanation:

The computation is shown below:

For land

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= $1,006,000 × $126,000 ÷ $900,000

= $140,840

For building

= Total purchase price × appraisal value of building ÷ total appraisal value

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= $509,707

For machinery

= Total purchase price × appraisal value of land ÷ total appraisal value

= $1,006,000 × $318,000 ÷ $900,000

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where, the total purchase price is

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3 0
1 year ago
The tool crib at a large manufacturing company is responsible for providing tools to the factory workers on demand. The tool cri
Semmy [17]

Answer:

6.4 minutes

Explanation:

Average small tool per day = 445

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Waiting time  =  

\frac{[445*(\sqrt{1} )]}{[2*[480-(445*1)]]}  (image of the operation on the attach file)

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Mullineaux Corporation has a target capital structure of 64 percent common stock, 9 percent preferred stock, and 27 percent debt
nlexa [21]

Answer:

10.02%

Explanation:

The computation of the WACC is shown below. The formula of WACC is shown below:

= (Weightage of debt × cost of debt)  + (Weightage of preferred stock) × (cost of preferred stock) + (Weightage of  common stock) × (cost of common stock)

= 27% × 7.6% × (1 - 0.40) + 9% × 5.9% + 64% × 12.9%

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8 0
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Akers Company sold bonds on July 1, 20X1, with a face value of $100,000. These bonds are due in 10 years. The stated annual inte
taurus [48]

Answer:

Bond Price = $86409.67366 rounded off to $86409.67

Explanation:

To calculate the price of the bond today, we will use the formula for the price of the bond. We assume that the interest rate provided is stated in annual terms. As the bond is a semi annual bond, the coupon payment, number of periods and semi annual YTM will be,

Coupon Payment (C) = 100000 * 0.06 * 6/12  = $3000

Total periods (n) = 10 * 2 = 20  

r or YTM = 0.08 * 6/12 = 0.04 or 4%

The formula to calculate the price of the bonds today is attached.

Bond Price = 3000 * [( 1 - (1+0.04)^-20) / 0.04]  + 100000 / (1+0.04)^20

Bond Price = $86409.67366 rounded off to $86409.67

8 0
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