A box weighing 25 pounds (assumed concentrated at its center of gravity) is being pulled by a horizontal force F equal to 20 pou
nds. What is the moment about point A? Does the box tip over
1 answer:
Answer:
(a)the moment about point A is zero
(b) the box does not tip
Explanation:
Consider the diagram of forces as shown in the diagram given in the attached document.
Given the pulling force F= 20 lb and the weight W= 25 lb. and given the height and length of the box to be 5ft and 8ft respectively. We take moment about A.
Moment is the product of force and the perpendicular distance from the line of action of a force.
It is clear that F act through the distance 5ft and W acts through 4ft.
Hence total clockwise moment =total anticlockwise moment
20 × 5 = 25 × 4
Or
Sum of all moment is zero
100-100 =0
The moment due to both forces are equal, hence there is equilibrium. Since there is
equilibrium the box does not tip.
You might be interested in
Answer:
Pressure = 11.38 psi
Force = 13.981 Ibf
Explanation:
Step by step solution is in the attached document.
Answer:
W = 12.8 KW
Explanation:
given data:
mass flow rate = 0.2 kg/s
Engine recieve heat from ground water at 95 degree ( 368 K) and reject that heat to atmosphere at 20 degree (293K)
we know that maximum possible efficiency is given as
rate of heat transfer is given as
Maximuim power is given as
W = 0.2038 * 62.7
W = 12.8 KW
Answer:
3180.86 Nm
Explanation:
Moment of inertia for shaft AB,
Torque in solid shaft AB will be given by
Where is shear stress,
is polar moment of inertia for shaft AB, r is the radius of shaft B
The inner diameter of pipe CD can found considering that the thickness of pipe is 0.006 m hence diameter= 0.09-(2*0.006)= 0.078 m
Moment of inertia for shaft CD will be
Torque for shaft CD will be
and here r = 0.045 m
The minimum of the two torques is the largest torque that can be applied. Therefore, the torque to apply equals 3180.86 Nm
