A solid copper bar of circular cross section has length L 5 1.25 m and shear modulus of elasticity G 5 45 GPa. The bar is design
ed to carry a 250 N m? torque acting at the ends. If the allowable shear stress is 30 MPa and the allowable angle of twist between the ends is 2.58, what is the minimum required diameter?
1 answer:
Answer:
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Explanation:
solid copper bar of circular cross section has length L 5 1.25 m and shear modulus of elasticity G 5 45 GPa. The bar is designed to carry a 250 N m? torque acting at the ends. If the allowable shear stress is 30 MPa and the allowable angle of twist between the ends is 2.58
Answers: dmin = 35.7mm
7 7 L=1.25 m
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Answer:
Explanation:
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Answer:
D. N= 11. 22 rad/s (CW)
Explanation:
Given that
Form factor R = 8
Speed of sun gear = 5 rad/s (CW)
Speed of ring gear = 12 rad/s (CW)
Lets take speed of carrier gear is N
From Algebraic method ,the relationship between speed and form factor given as follows
here negative sign means that ring and sun gear rotates in opposite direction
Lets take CW as positive and ACW as negative.
Now by putting the values
N= 11. 22 rad/s (CW)
So the speed of carrier gear is 11.22 rad/s clockwise.