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den301095 [7]
2 years ago
12

When 0.1523 g of liquid pentane (CH) combusts in a bomb calorimeter, the temperature rises from 23.7C to 29.8 C. What is U for t

he reaction in kJ/mol pentane? The heat capacity of the bomb calorimeter is 5.23 kJ/C.
Physics
1 answer:
pashok25 [27]2 years ago
8 0

Answer:

U for the reaction is 15,048.58 kJ/mol of pentane.

Explanation:

Quantity of heat required = heat capacity of bomb calorimeter × temperature rise = 5.23 kJ/C × (29.8 C - 23.7 C) = 5.23 kJ/C × 6.1 C = 31.903 kJ

Moles of pentane = mass/MW

Mass = 0.1523 g

MW of pentane (C5H12) = 72 g/mol

Moles of pentane = 0.1523/72 = 0.00212 mol

U for the reaction = quantity of heat required ÷ moles of pentane = 31.903 kJ ÷ 0.00212 mol = 15,048.58 kJ/mol

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5 0
2 years ago
A bar 4.0m long weights 400 N. Its center of gravity is 1.5m from on end. A weight of 300N is attached at the light end. What ar
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Now, the tricky part is the point of application, which involves rotational equilibrium. But this is quite simple if we write down an equation for dynamic momentum with respect to the heavy end (not the light end where the additional weight is placed). The condition is that the sum of momenta with respect to this (any) point of the solid bar is zero:

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