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2 years ago

500mL of He at 98 kPa expands to 750 mL. Find P2

Physics

1 answer:

GarryVolchara [31]2 years ago

3 0

The value of P₂ is 65.33 kPa

<u>Explanation:</u>

Given:

Volume, V₁ = 500mL

Pressure, P₁ = 98 kPa

Volume, V₂ = 750 mL

Pressure, P₂ = ?

According to Boyle's law:

P₁V₁ = P₂V₂

On substituting the value we get:

$98 X 500 = 750 X P_2\\\\P_2 = \frac{98 X 500}{750} \\\\P_2 = 65.33 kPa$

The value of P₂ is 65.33 kPa

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