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ikadub [295]
1 year ago
5

Select True or False for the following statements about Heisenberg's Uncertainty Principle. True False It is not possible to mea

sure simultaneously the x and y positions of a particle exactly.
True False It is not possible to measure simultaneously the x and y momentum components of a particle exactly.
True False It is not possible to measure simultaneously the z position and the z momentum component of a particle exactly.
Physics
1 answer:
sveticcg [70]1 year ago
6 0

Answer:

Statement 1) False

Statement 2) False

Statement 3) True

Explanation:

The uncertainty principle states that " in a physical system certain quantities cannot be measured with random precision no matter whatever the least count of the instrument is" or we can say while measuring simultaneously the position and momentum of a particle the error involved is

P\cdot\delta x\geq \frac{h}{4\pi }

Thus if we measure x component of momentum of a particle with 100% precision we cannot measure it's position 100% accurately as the error will be always there.

Statement 1 is false since measurement of x and y positions has no relation to uncertainty.

Statement 2 is false as both the momentum components can be measured with 100% precision.

Statement 3 is true as as demanded by uncertainty principle since they are along same co-ordinates.

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Kimonoski takes a 9-minute shower every day. The shower uses about 1.8 gal per minute of water. He also uses 23 gallons of hot w
ioda

Answer:

Q_{week} = 458884.6\, BTU

Explanation:

The weekly water consumption of Kimonoski is:

m_{bath,week} = (62.4\,\frac{lbm}{ft^{3}})\cdot (1.8\,\frac{gal}{min} )\cdot (\frac{0.134\,ft^{3}}{1\,gal} )\cdot (\frac{1\,min}{60\,s} )\cdot (9\,min)\cdot (\frac{60\,s}{1\,min} )\cdot (7\,\frac{days}{week} )\cdot (1\,week)

m_{bath.week} = 948.205\,lbm

m_{others, week} = (62.4\,\frac{lbm}{ft^{3}})\cdot (23\,gal)\cdot (\frac{0.134\,ft^{3}}{1\,gal} )\cdot (7\,\frac{days}{week} )\cdot (1\,week)

m_{others, week} = 1346.218\,lbm

m_{week} = m_{bath,week} + m_{others, week}

m_{week} = 2294.423\,lbm

The total energy required per week for hot water is:

Q_{week} = m_{week}\cdot c_{p,water}\cdot \Delta T

Q_{week} =(2294.423\,lbm)\cdot (1\,\frac{BTU}{lbm\cdot ^{\textdegree}F} )\cdot (50^{\textdegree}F)

Q_{week} = 458884.6\, BTU

3 0
1 year ago
Robin Hood wishes to split an arrow already in the bull's-eye of a target 40 m away.
tamaranim1 [39]

Answer:

5.843 m

Explanation:

suppose that the arrow leave the bow with a horizontal speed , towards he bull's eye.

lets consider that horizontal motion

distance = speed * time

time = 40/ 37 = 1.081 s

arrow doesnot have a initial vertical velocity component. but it has a vertical motion due to gravity , which may cause a miss of the target.

applying motion equation

(assume g = 10 m/s²)

s=ut+\frac{1}{2}*gt^{2}  \\= 0+\frac{1}{2}*10*1.081^{2}\\= 5.843 m

Arrow misses the target by 5.843m ig the arrow us split horizontally

4 0
1 year ago
Coffee is poured at a uniform rate at 20 cm3 / s into a cup whose inside is shaped like a truncated cone. if the upper and lower
Vladimir [108]

Let the cup is filled to height h after some time

now the total volume of coffee filled in the cup is given as

\frac{2}{y} = \frac{4}{6+y}

2y = 6 + y

y = 6 cm

now volume of the coffee will be

V = \frac{1}{3}\pi r^2(y + 6) - \frac{1}{3}\pi 2^2 (6)

here we know that

\frac{r}{y+6} = \frac{2}{6}

r = \frac{y+6}{3}

V = \frac{1}{3}\pi (\frac{y+6}{3})^2(y+6) - \frac{1}{3}\pi 2^2(6)

now we know that volume flow rate is given as

Q = \frac{dV}{dt}

20 cm^3/s = \frac{1}{3}\pi (\frac{1}{9})(3(y+6)^2)\frac{dy}{dt}

20 \times 9 = \pi (y + 6)^2 v

here y = 3 cm

180 = \pi (9)^2 v

v = 0.71 cm/s

so water will rise up with speed 0.71 cm/s


5 0
2 years ago
Centripetal force Fc acts on a car going around a curve. If the speed of the car were twice as great, the magnitude of the centr
kondaur [170]

Answer:

We need 4 times more force to keep the car in circular motion if the velocity gets double.

Explanation:

Lets take the mass of the car = m

The radius of the arc = r

F=\frac{m\times v^2}{r}

Given that speed of the car gets double ,v' = 2 v

Then the force on the car = F'

F'=\frac{m\times v'^2}{r}  ( radius of the arc is constant)

F'=\frac{m\times (2v)^2}{r}

F'=4\times \frac{m\times v^2}{r}

We know that F=\frac{m\times v^2}{r}

Therefore F' = 4 F

So we can say that we need 4 times more force to keep the car in circular motion if the velocity gets double.

6 0
1 year ago
A pulley system used to lift car tires has a mechanical advantage of 11.2. If you pull on the pulley with a force of 150 N, how
Novay_Z [31]
1680 is the answer i got because i did this problem in apex
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1 year ago
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