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Mademuasel [1]
2 years ago
5

In january, wally's widget world had sales of $12,500 and expenses of $10,200. the profit for january was _____. 2,300 7,900 10,

200 22,700
Mathematics
2 answers:
kotykmax [81]2 years ago
4 0
2,300
I hope this helps!
uranmaximum [27]2 years ago
4 0

Answer:

Option A is correct.

the profit for January was $2,300

Step-by-step explanation:

As per the statement:

In January, wally's widget world had sales of $12,500 and expenses of $10,200

⇒wally's widget world had sales(S.P) = $12,00 and expenses = $10,200.

By using formula:

\text{Profit} = \text{Sales} - \text{Expenses}

Substitute the given value we have;

\text{Profit} = 12500-10200 =\$ 2300

Therefore,  the profit for January was $2,300

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Order the numbers from smallest to largest: 1.448, 2 , 14 10 , and 1.22, A) 14 10 , 2 , 1.22, 1.448 B) 14 10 , 1.22, 1.448, 2 C)
LekaFEV [45]

Answer:

1.448 - 1.22 - 2 - 1,410

Step-by-step explanation:

smallest ------ Largest

4 0
2 years ago
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"A consultant compiled the following data set that shows" the number of visits made to the National Museum of American History f
aalyn [17]

Answer:

Step-by-step explanation:

The best option is for the consultant to remove these data points because they are outliers.  Unusual data points which are located far from rest of the data points are known as outliers.

3 0
2 years ago
Josh works for a construction company that uses 150 pounds of gravel for each driveway they pour. He can buy a dump truck load w
Pavlova-9 [17]

Answer:

Josh should by the dump truck with 30,000 pounds of gravel in it

Step-by-step explanation:

the easiest way to find this out is divide 30,000 and 2,500 by 150 and if the answer is a whole number, then you know that is the correct answer.

30,000/150 = 200

2,500/150 = 16.6666666666666

May I have brainliest please? :)

5 0
2 years ago
Suppose you roll a pair of honest dice. If you roll a total of 7 you win $22, if you roll a total of 11 you win $66, if you roll
JulijaS [17]

Answer:

The expected payoff for this game is -$1.22.

Step-by-step explanation:

It is given that a pair of honest dice is rolled.

Possible outcomes for a dice = 1,2,3,4,5,6

Two dices are rolled then the total number of outcomes = 6 × 6 = 36.

\{(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),\\(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),\\(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)\}

The possible ways of getting a total of 7,

{ (1,6), (2,5), (3,4), (4,3), (5,2), (6,1) }

Number of favorable outcomes = 7

Formula for probability:

Probability=\frac{\text{Favorable outcomes}}{\text{Total outcomes}}

So, the possibility of getting a total of 7 = \frac{6}{36}=\frac{1}{6}

The possible ways of getting a total of 11,

{(5,6), (6,5)}

So, the probability of getting a total of 11 = \frac{2}{36} = \frac{1}{18}

Now, other possible rolls = 36 - 6 - 2 = 36 - 8 = 28,

So, the probability of getting the sum of numbers other than 7 or 11 = \frac{28}{36} = \frac{7}{9}

Since, for the sum of 7, $ 22 will earn, for the sum of 11, $ 66 will earn while for any other total loss is $11,

Hence, the expected value for this game is

\frac{1}{6}\times 22+\frac{1}{18}\times 66-\frac{7}{9}\times 11

\frac{11}{3}+\frac{11}{3}-\frac{77}{9}

\frac{22}{3}-\frac{77}{9}

\frac{66-77}{9}

-\frac{11}{9}

-1.22

Therefore the expected payoff for this game is -$1.22.

4 0
2 years ago
Total employment for sheet metal workers in 2016 is projected to be 201,000. if this is a 6.3% increase from 2006, approximately
fomenos

Answer:

Option d.

Step-by-step explanation:

Total employment for sheet metal workers in 2016 is projected to be = 201,000

This is a 6.3% increase from 2006.

Let the number of workers in 2006 be n

n + (6.3% of n) = 201,000

n + ( 0.063n) = 201,000

1.063n = 201,000

n = \frac{201,000}{1.063}

n = 189,087. 4882 ≈ 189,000

the total employment in 2006 was approximately 189,000

Option d is the answer.

8 0
2 years ago
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