It doesn't matter if the ages are odd or even - there is two years between each child in age.
The sum would be x + x + 2 + x + 4 or 3x + 6. Lets try it with a sample age. Let's say the youngest is 5 middle is 7 and oldest is 9 The sum of their ages is 21 (5 + 7 + 9)
Using our answer of 3x + 6 where x is the age of the youngest child, we get 3(5) +6 which is also 21.
This could also be solved by having x represent the middle age child x-2 is the youngest (2 years less than the middle) x = the middle x+2 is the oldest (2 years older than the middle)
The sum of these would be x-2 + x + x +2 or simply 3x (the 2's cancel out) Since the middle child is 7 3x would mean 3 (7)=21
You could also set this up using x for the oldest child x= oldest x-2= middle x-4= youngest (The sum of this is 3x - 6)
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