<span> If P(x) is a polynomial with integer coefficients and if is a zero of P(x) ( P( ) = 0 ), then p is a factor of the constant term of P(x) and q is a factor of the leading coefficient of P(x) .
</span><span>A. x – 6
</span><span>60(6)^4 + 86(6)^3 – 46(6)^2 – 43(6) + 8 = 94430
</span><span>
B. 5x – 8
</span>60(8/5)^4 + 86(8/5)^3 – 46(8/5)^2 – 43(8/5) + 8 = 566.912<span>
C. 6x – 1
</span>60(1/6)^4 + 86(1/6)^3 – 46(1/6)^2 – 43(1/6) + 8 = 0 -------> ANSWER
<span>
D. 8x + 5
</span>60(-5/8)^4 + 86(-5/8)^3 – 46(-5/8)^2 – 43(-5/8) + 8 = 5.07
19+4n is the answer and i m sure
Answer:
chances chances of happening = 0.0119
Step-by-step explanation:
given data
bet = $5
independent fair games = 50
solution
we will think game as the normal distribution
so here mean is will be
mean = 
mean = 25
and standard deviation will be
standard deviation = 
standard deviation = 3.536
so
we have to lose 33 out of 50 time for lose more than $75
so as chance of doing things z score is
z score =
z score = 2.26
so from z table
chances chances of this happening = 0.0119