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Alexxandr [17]
2 years ago
10

In class we derived the MOM and MLE for an exponential distribution with parameter ????. Conduct a Bootstrap simulation to compa

re the estimation of λ with sample sizes of n = 10, n = 100, and n = 500. Choose true value λ = 0.2 and use B = 1000. Calculate and compare the mean and standard error for each set of simulations to each other as well as their theoretical values.

Mathematics
1 answer:
Dimas [21]2 years ago
8 0

Answer:

Below is the R code for the bootstrapping in exponential distribution. The result is attached below.

####################################

rm(list=ls(all=TRUE))

set.seed(12345)

N=c(10,100,500)

Rate=0.2

B=1000

MN=SE=rep()

for(i in 1:length(N))

{

n=N[i]

X=rexp(n,rate=Rate)

EST=1/mean(X)

ESTh=rep()

for(j in 1:B)

{

Xh=rexp(n,rate=EST)

ESTh[j]=1/mean(Xh)

}

MN[i]=mean(ESTh)

SE[i]=sd(ESTh)

}

cbind(N,Rate,MN,SE)

Step-by-step explanation:

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Area=height times base (for some prisms including cylinders)
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vcylinder=height times aeraofbase

 

given
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v=324pi
324pi=9(basearea)
divide both sides by 9
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2 years ago
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An empty can weighs 30 grams. The weight of the same can filled with liquid is 47.3 grams. Which equation could be used to find
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Answer:

w = y - x is the equation to find w

Where,

w = Weight of the liquid

x = Weight of the empty can

y = Weight of the can with liquid

Step-by-step explanation:

Let

Weight of the empty can = x

Weight of the liquid = w

Weight of the can with liquid = x + w = y

x= 30 grams

w = ?

y= 47.3 grams

y = x + w

w = y - x

= 47.3 - 30

= 17.3

w= 17.3 grams

Therefore, the weight of the liquid is 17 .3 grams

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2 years ago
Forty more than twice malia's age is 64
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12 x 2+40=64

Malia is 12 years old.


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2 years ago
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A local fraternity is conducting a raffle where 55 tickets are to be sold—one per customer. There are three prizes to be awarded
harkovskaia [24]

Answer:

(a) 0.0152%

(b) 1.1663%

(c) 19.4297%

(d) 79.3787%

Step-by-step explanation:

Tickets bought by organizers = 4

Number of tickets = 55

Prizes = 3

(a) The probability that the four organizers win all of the prizes is:

P = \frac{4}{55}*\frac{3}{54}*\frac{2}{53}\\P=0.0152\%

(b) The probability that the four organizers win exactly two of the prizes is:

P = \frac{4}{55}*\frac{3}{54}*\frac{51}{53}+\frac{4}{55}*\frac{51}{54}*\frac{3}{53}+\frac{51}{55}*\frac{4}{54}*\frac{3}{53}\\P=1.1663\%

(c) The probability that the four organizers win exactly one of the prizes is:

P = \frac{4}{55}*\frac{51}{54}*\frac{50}{53}+\frac{51}{55}*\frac{4}{54}*\frac{50}{53}+\frac{51}{55}*\frac{50}{54}*\frac{4}{53}\\P=19.4397\%

(d) The probability that the four organizers win none of the prizes is:

P = \frac{51}{55}*\frac{50}{54}*\frac{49}{53}}\\P=79.3787\%

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2 years ago
A loaf of sandwich bread contains 24 slices. Which of these tables correctly shows the ratios of different numbers of loaves of
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Answer:

15

Step-by-step explanation: i'm not explaining why

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