Answer:
Metal inert gas or Metal Active Gas
Explanation:
Gas Metal Arc Welder(GMAW) also is also termed as Metal Inert Gas(MIG) welder or Metal Active Gas (MAG) welder.
Gas Metal Arc welding is a process in which 2 metal pieces are melted through the use of electricity and joined together. A continuous wire is fed through the welding gun, which heats up the metal. This type of welding was introduced back in 1949 and was used for welding of Aluminium.
Answer:
153.2 J
Explanation:
Let's first list our given parameters;
mass (m) of the block = 10 kg
which slides down ( i.e displacement) = 2 m
kinetic coefficient of friction (μk) = 0.2
In the diagram shown below; if we take an integral look at the component of force in the direction of the displacement; we have
Fcos 40°
100 (cos 40°)
76.60 N
Workdone by the friction force can now be determined as:
W = 
× displacement
W = 76.60 × 2
W = 153.2 J
∴ the work done by the friction force = 153.2 J
Answer:
\epsilon = 0.028*0.3 = 0.0084
Explanation:
\frac{P_1}{\rho} + \frac{v_1^2}{2g} +z_1 +h_p - h_l =\frac{P_2}{\rho} + \frac{v_2^2}{2g} +z_2
where P_1 = P_2 = 0
V1 AND V2 =0
Z1 =0
h_P = \frac{w_p}{\rho Q}
=\frac{40}{9.8*10^3*0.2} = 20.4 m
20.4 - (f [\frac{l}{d}] +kl) \frac{v_1^2}{2g} = 10
we know thaTV =\frac{Q}{A}
V = \frac{0.2}{\pi \frac{0.3^2}{4}} =2.82 m/sec
20.4 - (f \frac{60}{0.3} +14.5) \frac{2.82^2}{2*9.81} = 10
f = 0.0560
Re =\frac{\rho v D}{\mu}
Re =\frac{10^2*2.82*0.3}{1.12*10^{-3}} =7.53*10^5
fro Re = 7.53*10^5 and f = 0.0560
\frac{\epsilon}{D] = 0.028
\epsilon = 0.028*0.3 = 0.0084
Then I walked into Mr. and Mrs. Frank's bedroom. On the floor, amidst the chaos of papers and books, my eye lit on the little red-orange checkered, cloth-bound diary that Anne had received from her father on her thirteenth birthday. She loves Anne and respects her work.
I hope this helps you.
